杭电1012--u Calculate e

u Calculate e

Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 35178    Accepted Submission(s): 15843

Problem Description

A simple mathematical formula for e is



where n is allowed to go to infinity. This can actually yield very accurate approximations of e using relatively small values of n.

 

 

Output

Output the approximations of e generated by the above formula for the values of n from 0 to 9. The beginning of your output should appear similar to that shown below.

 

 

Sample Output

n e 

- ----------- 

0 1 

1 2 

2 2.5 

3 2.666666667 

4 2.708333333

 

 

 

Source

Greater New York 2000

 

//水题，格式； 

 1 #include<stdio.h>

 2 double sieve[100];

 3 int main()

 4 {

 5     int i, total=1; sieve[0]=1;

 6     for(i=1;i<10;i++)

 7     {

 8         total*=i;

 9         sieve[i]=sieve[i-1]+1.0/total;    

10     }

11     printf("n e\n");

12     printf("- -----------\n");

13     int n;

14     for(i=0;i<10;i++)

15     {

16         printf("%d ",i);

17         if(i<=1)

18         printf("%d\n",(int)sieve[i]);

19         else if(i==2)

20         printf("%.1lf\n",sieve[i]);

21         else

22         printf("%.9lf\n",sieve[i]);

23     }

24     return 0;

25 }