python s=1*2-2*3+ 3*4-4*5+..+(-1)m1XnX

计算
s=12-23+ 34-45+…+(-1)m1XnX
参考了网络上c++的代码
代码

@author: Catwang
"""
def sum_go(sum_to):
    sum_all = 0
    n = int(input('n='))
    for i in range(n):
        sum_all += (i+1)*(i+2) * (-1) ** (2 + i)
    return sum_all
 
if __name__ == '__main__':
    result = sum_go(sum_to=100)
    print(result)

运行结果