PAT 1026 程序运行时间
链接::http://www.patest.cn/contests/pat-b-practise/1026
代码:
#include
#include
#include
#include
#include
using namespace std;
int main()
{
int a,b,c,d,f,g;
scanf("%d%d",&a,&b);
c=b-a;
if(c/10%10>=5)
c=c/100+1;
else
c=c/100;
d=c/3600;
f=c%3600/60;
g=c%60;
if(d<10)
printf("0%d:",d);
else
printf("%d:",d);
if(f<10)
printf("0%d:",f);
else
printf("%d:",f);
if(g<10)
printf("0%d",g);
else
printf("%d",g);
return 0;
}
链接:http://www.patest.cn/contests/pat-b-practise/1027
代码:
#include
#include
#include
#include
#include
using namespace std;
int main()
{
char c;
int n,m,high=0,width,r=0;
scanf("%d %c",&n,&c);
if(n<7)
{
printf("%c\n%d\n",c,n-1);
return 0;
}
m=n;
for(int i=1;;++high,i+=2)
{
if(i==1)
{
width=i;
m-=width;
}
else
{
width=i;
m-=(width*2);
}
if(m<(i+2)*2)
{
++high;
r=m;
break;
}
}
//printf("%d %d\n",width,high);
for(int i=0;i
PAT 1028 人口普查
链接:http://www.patest.cn/contests/pat-b-practise/1028
代码:注意符合条件的人数可能为0
#include
#include
#include
#include
#include
using namespace std;
struct person
{
int y,m,d;
string name;
} p,oldest,youngest;
int st,en;
int cal(struct person tmp)
{
return (tmp.y-1814)*365+tmp.m*30+tmp.d;
}
bool check()
{
if(cal(p)en) return false;
if(cal(p)>=cal(youngest))
{
youngest.name=p.name;
youngest.y=p.y;
youngest.m=p.m;
youngest.d=p.d;
}
if(cal(p)<=cal(oldest))
{
oldest.name=p.name;
oldest.y=p.y;
oldest.m=p.m;
oldest.d=p.d;
}
return true;
}
int main()
{
int n,countx=0;
char c[10];
scanf("%d",&n);
youngest.y=1814;
youngest.m=9;
youngest.d=6;
oldest.y=2014;
oldest.m=9;
oldest.d=6;
st=9*30+6;
en=200*365+9*30+6;
for(int i=0; i
PAT 1029 旧键盘
链接:http://www.patest.cn/contests/pat-b-practise/1029
代码:
#include
#include
#include
#include
#include
#include
using namespace std;
set charSet;
int main()
{
bool flag;
char s1[100],s2[100];
scanf("%s%s",s1,s2);
//printf("%s\n%s\n",s1,s2);
int len1=strlen(s1);
int len2=strlen(s2);
for(int i=0,j=0; i
PAT 1030 完美数列
链接:http://www.patest.cn/contests/pat-b-practise/1030
代码:
#include
#include
#include
#include
#include
#include
using namespace std;
double v[100005];
int main()
{
int n,maxx=0;
double p;
scanf("%d%lf",&n,&p);
for(int i=0;imaxx)
maxx =j-i+1;
}
printf("%d\n",maxx);
return 0;
}