<一道题>abc+cba=1333,求满足条件的abc的值，隐含条件a!=0,c!=0

这类东西，无非就是穷举法。见下面代码：

#include <stdio.h>

#include <stdlib.h>



/*

*abc + cba = 1333 

*

*a = ?

*b = ?

*c = ?

*/







int main(int argc ,char **argv)

{

    int a=0;

    int b=0;

    int c=0;

    

    int index = 0;



    printf("abc + cba == 1333\n");

    

    for(a = 1 ; a <= 9 ; a++)//a [1,9]

    {

        for(b = 0 ; b <= 9; b++)//b [0,9]

        {

            for(c = 1 ; c <= 9; c++)//c [1,9]

            {

                if(1333 == (100*a + 10*b + c + 100*c + 10*b + a))

                {

                    index++;

                    printf("I have found it !!! index : %d , a= %d, b= %d, c=%d\n",index,a,b,c);//多谢1楼仁兄，找到了，却没有注意英文语法，已改found及I

                    

                }

            }

        }

    }



    printf("find over\n");

    return 0;

}

运行结果;

tiger@ubuntu:/mnt/hgfs/e/Lessons/MyExercise/UtilLibs/EXERCISE$ ./abc
abc + cba == 1333
I have found it !!! index : 1 , a= 4, b= 1, c=9
I have found it !!! index : 2 , a= 5, b= 1, c=8
I have found it !!! index : 3 , a= 6, b= 1, c=7
I have found it !!! index : 4 , a= 7, b= 1, c=6
I have found it !!! index : 5 , a= 8, b= 1, c=5
I have found it !!! index : 6 , a= 9, b= 1, c=4
find over
tiger@ubuntu:/mnt/hgfs/e/Lessons/MyExercise/UtilLibs/EXERCISE$