Python开发之list中的多重嵌套合并去重

前言：做数据处理这一块，少不了得数据去重这一块，今天趁此机会，总结一下list常用的去重，第三个是重点全网独此一分，还希望大家多给给关注！

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(一)list的一般去重问题

1.set去重

代码：

if __name__ == '__main__':
    list1 = [11, 22, 11, 22, 33, 44, 55, 55, 66]
    new_list1 = list(set(list1))
    print(list1)
    print(new_list1)

输出：

2.fromskey去重

代码：

if __name__ == '__main__':
    name_list = ["fly1","fly2","fly3","fly1","fly2","fly3","fly1","fly2","fly3"]
    new_name_list = list({
     }.fromkeys(name_list).keys())
    print(name_list)
    print(new_name_list)

输出：

3.遍历去重

代码：

if __name__ == '__main__':
    list1 = ["fly1","fly2","fly3","fly1","fly2","fly3","fly1","fly2","fly3"]
    list2 = []
    for i in list1:
        if i not in list2:
            list2.append(i)
    print(list1)
    print(list2)

输出：

(二)list中的字典去重

实现原理：借助functools里面的reduce函数，然后利用lambda函数实现list中的字典去重。
代码：

from functools import reduce

if __name__ == '__main__':
    data_list = [{
     "a": "123", "b": "321"}, {
     "a": "123", "b": "321"}, {
     "b": "321", "a": "123"}]
    new_data_list = reduce(lambda x, y: x if y in x else x + [y], [[], ] + data_list)
    print(data_list)
    print(new_data_list)

(三)list中的多重嵌套合并去重问题

请看上图，我们需要处理的结果是把两个list合并成一个list，并且里面的字典重复的只需要保留一个，name一样的需要进一步判断info集合里面的数据是不是一样，一样的话才是重复数据，不一样的话，追加到info集合中去。
list1的数据集合是：

list2的数据集合是：

两个集合合并去重之后的是：

代码：

import json

def get_data1_list():
    data_list = [{
     "name": "fly1", "cishu": 2, "info": [{
     "java": 80, "python": 100, "c": 60},{
     "java": 81, "python": 101, "c": 60}]},
                  {
     "name": "fly2", "cishu": 1, "info": [{
     "java": 81, "python": 101, "c": 61}]},
                  {
     "name": "fly3", "cishu": 1, "info": [{
     "java": 82, "python": 102, "c": 62}]},
                  {
     "name": "fly4", "cishu": 1, "info": [{
     "java": 80, "python": 103, "c": 63}]},
                  {
     "name": "fly5", "cishu": 1, "info": [{
     "java": 83, "python": 104, "c": 64}]}]
    return data_list

def get_data2_list():
    data_list = [{
     "name": "fly1", "cishu": 1, "info": [{
     "java": 80, "python": 100, "c": 61}]},
                  {
     "name": "fly2", "cishu": 1, "info": [{
     "java": 81, "python": 101, "c": 61}]},
                  {
     "name": "fly3", "cishu": 1, "info": [{
     "java": 82, "python": 102, "c": 62}]},
                  {
     "name": "fly7", "cishu": 1, "info": [{
     "java": 87, "python": 103, "c": 67}]},
                  {
     "name": "fly8", "cishu": 1, "info": [{
     "java": 88, "python": 104, "c": 68}]}]
    return data_list


if __name__ == '__main__':

    data_list = get_data1_list()+get_data2_list()
    name_list = []

    for data in data_list:
        name = data["name"]
        name_list.append(name)

    print("合并之前的长度",len(name_list))
    new_name_list = list({
     }.fromkeys(name_list).keys())
    print("合并之后的长度",len(new_name_list))

    ll = []
    for new_company in new_name_list:
        new_list = []
        for data in data_list:
            if data["name"] == new_company:
                d = [False for c in data["info"] if c not in new_list]
                if d:
                    new_list += data["info"]
                    print('{} not in new_list'.format(data["info"]))
                else:
                    print('{} in new_list'.format(data["info"]))
        dict = {
     "name":new_company,"cishu":len(new_list),"info":new_list}
        new_list = []
        ll.append(dict)
    print(json.dumps(ll,ensure_ascii=False,indent=2))

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