ISO C++ forbids declaration of 'iterator' with no type

xcode下编译报错:ISO C++ forbids declaration of 'iterator' with no type

出错点:

template<class T>

class MyVector: public std::vector<T>

{

public:

	typedef std::vector<T> vecType;

	typedef vecType::iterator vecIterator; //报错



	MyVector(){};

	MyVector(const vecType& _vec);

	//.......

	//.......

};

根据别人的回答,http://stackoverflow.com/questions/1732895/error-iso-c-forbids-declaration-of-iterator-with-no-type。找到原因:

“The reason being being that iterator is dependent on what T is, so the compiler can't be sure it's a typename unless you tell it.”

加 typename,修改后编译通过:

template<class T>

class MyVector: public std::vector<T>

{

public:

	typedef std::vector<T> vecType;

	typedef typename vecType::iterator vecIterator; //typename



	MyVector(){};

	MyVector(const vecType& _vec);

	//.......

	//.......

};

mark! 还有一点“C++编译器不能支持对模板的分离式编译”,why? google.....

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