C++编程练习 计算一元二次方程组解&判断是否测试过三种情况

原题来自菜鸟教程
C++ 实例 - 求一元二次方程的根

实现方法相当简单 就是最基础的C语言程序
以下是菜鸟教程给的答案——

#include 
#include 
using namespace std;
 
int main() {
     
 
    float a, b, c, x1, x2, discriminant, realPart, imaginaryPart;
    cout << "输入 a, b 和 c: ";
    cin >> a >> b >> c;
    discriminant = b*b - 4*a*c;
    
    if (discriminant > 0) {
     
        x1 = (-b + sqrt(discriminant)) / (2*a);
        x2 = (-b - sqrt(discriminant)) / (2*a);
        cout << "Roots are real and different." << endl;
        cout << "x1 = " << x1 << endl;
        cout << "x2 = " << x2 << endl;
    }
    
    else if (discriminant == 0) {
     
        cout << "实根相同：" << endl;
        x1 = (-b + sqrt(discriminant)) / (2*a);
        cout << "x1 = x2 =" << x1 << endl;
    }
 
    else {
     
        realPart = -b/(2*a);
        imaginaryPart =sqrt(-discriminant)/(2*a);
        cout << "实根不同："  << endl;
        cout << "x1 = " << realPart << "+" << imaginaryPart << "i" << endl;
        cout << "x2 = " << realPart << "-" << imaginaryPart << "i" << endl;
    }
 
    return 0;
}

嗯 自己也很快就实现了这个功能
但是在进行测试的时候



啊三种情况好烦啊 还得一遍遍地编译运行（明明这样更快啊喂！
有没有啥方法可以一遍试完这三种情况呢。

加个计数器吧
嗯 perfect~

#include
#include
using namespace std;

int main()
{
     
	int count,counta,countb,countc;
	
	float det,x1,x2,a,b,c;
	float realPart,imaginaryPart;
	
	while(count != 1){
     
		cout << "please input the parameter:" << endl;
		cin >> a >> b >> c;
	
		det = b*b - 4*a*c;
	
			
		if(det > 0){
     
			cout << "the roots are real and different" << endl;
			x1 = (-b + sqrt(det))/(2*a);
			x2 = (-b - sqrt(det))/(2*a);
			cout << "x1 = " << x1 << endl;
			cout << "x2 = " << x2 << endl;
			counta = 1;

		}
	
		else if(det == 0){
     
			cout << "the root is equal" << endl;
			x1 = x2 = -b/(2*a);
			cout << "x1 = x2 =  "<< x1 << endl;
			countb = 1;

	
		}	
//	det<0 两个根是复数（跟高中讲的不太一样嗷） 两个复数根为共轭复根 
		else {
     
			cout << "一对共轭复根出现辽" << endl;
			
			realPart = -b/(2*a);
			imaginaryPart = ( -sqrt(det) ) / (2*a);
			
			if (imaginaryPart){
     
//				复数中的b不存在的情况 
				cout << "x1 = " << realPart << endl;
				cout << "x2 = " << realPart << endl;
				countc = 1;
			}
			else{
     
				cout << "x1 = " << realPart << '+' << imaginaryPart << 'i' << endl;
				cout << "x2 = " << realPart << '-' << imaginaryPart << 'i' << endl;
				countc = 1;//计数器 
			}
			

		}
			if(counta==1 && countb==1 && countc==1){
     
				count = 1;
			}
	}
	cout << "duang----------------------------------duang" << endl;
	cout << "已经试过了det>0 det=0 det<0 三种情况咯~" << endl;
	 
	
	
}

终于可以愉快地一遍测试完成了呢。。
（工作量貌似增加了的亚子