LeetCode-python 344.反转字符串

题目链接
难度：简单       类型： 数组

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编写一个函数，其作用是将输入的字符串反转过来。输入字符串以字符数组 char[] 的形式给出。

不要给另外的数组分配额外的空间，你必须原地修改输入数组、使用 O(1) 的额外空间解决这一问题。

你可以假设数组中的所有字符都是 ASCII 码表中的可打印字符。

示例1

输入：["h","e","l","l","o"]
输出：["o","l","l","e","h"]

示例2

输入：["H","a","n","n","a","h"]
输出：["h","a","n","n","a","H"]

解题思路

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双指针，start指向头，end指向尾，两个指针指向的元素交换，之后start加1，end减1，继续交换

代码实现

class Solution(object):
    def reverseString(self, s):
        """
        :type s: List[str]
        :rtype: None Do not return anything, modify s in-place instead.
        """
        start = 0
        end = len(s)-1
        while start

本文链接：https://www.jianshu.com/p/eb95bd76090f