Masonry笔记

- (NSArray *)mas_makeConstraints:(void(^)(MASConstraintMaker *make))block;

- (NSArray *)mas_updateConstraints:(void(^)(MASConstraintMaker *make))block;

- (NSArray *)mas_remakeConstraints:(void(^)(MASConstraintMaker *make))block;

/*

mas_makeConstraints 只负责新增约束 Autolayout不能同时存在两条针对于同一对象的约束 否则会报错

mas_updateConstraints 针对上面的情况 会更新在block中出现的约束 不会导致出现两个相同约束的情况

mas_remakeConstraints 则会清除之前的所有约束 仅保留最新的约束

三种函数善加利用 就可以应对各种情况了

*/

make.edges.equalTo(sv).with.insets(UIEdgeInsetsMake(10, 10, 10, 10));

/* 等价于

make.top.equalTo(sv).with.offset(10);

make.left.equalTo(sv).with.offset(10);

make.bottom.equalTo(sv).with.offset(-10);

make.right.equalTo(sv).with.offset(-10);

*/

/* 也等价于

make.top.left.bottom.and.right.equalTo(sv).with.insets(UIEdgeInsetsMake(10, 10, 10, 10));

*/

//and与with什么事情也没有做

- (MASConstraint *)with {    return self;}

- (MASConstraint *)and {    return self;}

eg:让两个高度为150的view垂直居中且等宽且等间隔排列 间隔为10(自动计算其宽度)

int padding1 = 10;

[sv2 mas_makeConstraints:^(MASConstraintMaker *make) {

make.centerY.mas_equalTo(sv.mas_centerY);

make.left.equalTo(sv.mas_left).with.offset(padding1);

make.right.equalTo(sv3.mas_left).with.offset(-padding1);

make.height.mas_equalTo(@150);

make.width.equalTo(sv3);//****

}];

[sv3 mas_makeConstraints:^(MASConstraintMaker *make) {

make.centerY.mas_equalTo(sv.mas_centerY);

make.left.equalTo(sv2.mas_right).with.offset(padding1);

make.right.equalTo(sv.mas_right).with.offset(-padding1);

make.height.mas_equalTo(@150);

make.width.equalTo(sv2);//****

}];

自动算宽度的秘籍在于

/*

int padding1 = 10;//先写好间距

make.width.equalTo(sv3);//两个View中都要写对方

make.width.equalTo(sv2);//两个View中都要写对方

*/