POJ-1222 EXTENDED LIGHTS OUT 高斯消元

  题目链接:http://poj.org/problem?id=1222

  异或高斯消元。

  1 //STATUS:C++_AC_0MS_156KB

  2 #include <functional>

  3 #include <algorithm>

  4 #include <iostream>

  5 //#include <ext/rope>

  6 #include <fstream>

  7 #include <sstream>

  8 #include <iomanip>

  9 #include <numeric>

 10 #include <cstring>

 11 #include <cassert>

 12 #include <cstdio>

 13 #include <string>

 14 #include <vector>

 15 #include <bitset>

 16 #include <queue>

 17 #include <stack>

 18 #include <cmath>

 19 #include <ctime>

 20 #include <list>

 21 #include <set>

 22 #include <map>

 23 using namespace std;

 24 //using namespace __gnu_cxx;

 25 //define

 26 #define pii pair<int,int>

 27 #define mem(a,b) memset(a,b,sizeof(a))

 28 #define lson l,mid,rt<<1

 29 #define rson mid+1,r,rt<<1|1

 30 #define PI acos(-1.0)

 31 //typedef

 32 typedef long long LL;

 33 typedef unsigned long long ULL;

 34 //const

 35 const int N=35;

 36 const int INF=0x3f3f3f3f;

 37 const int MOD=100000,STA=8000010;

 38 const LL LNF=1LL<<60;

 39 const double EPS=1e-8;

 40 const double OO=1e15;

 41 const int dx[4]={-1,0,1,0};

 42 const int dy[4]={0,1,0,-1};

 43 const int day[13]={0,31,28,31,30,31,30,31,31,30,31,30,31};

 44 //Daily Use ...

 45 inline int sign(double x){return (x>EPS)-(x<-EPS);}

 46 template<class T> T gcd(T a,T b){return b?gcd(b,a%b):a;}

 47 template<class T> T lcm(T a,T b){return a/gcd(a,b)*b;}

 48 template<class T> inline T lcm(T a,T b,T d){return a/d*b;}

 49 template<class T> inline T Min(T a,T b){return a<b?a:b;}

 50 template<class T> inline T Max(T a,T b){return a>b?a:b;}

 51 template<class T> inline T Min(T a,T b,T c){return min(min(a, b),c);}

 52 template<class T> inline T Max(T a,T b,T c){return max(max(a, b),c);}

 53 template<class T> inline T Min(T a,T b,T c,T d){return min(min(a, b),min(c,d));}

 54 template<class T> inline T Max(T a,T b,T c,T d){return max(max(a, b),max(c,d));}

 55 //End

 56 

 57 int ma[N][N],A[N][N],B[N];

 58 int T;

 59 

 60 void getA(int n,int m)

 61 {

 62     int i,j,k,x,y;

 63     mem(A,0);

 64     for(i=0;i<n;i++){

 65         for(j=0;j<m;j++){

 66             A[i*6+j][i*6+j]=1;

 67             for(k=0;k<4;k++){

 68                 x=i+dx[k];

 69                 y=j+dy[k];

 70                 if(x>=0&&x<n && y>=0&&y<m){

 71                     A[i*6+j][x*6+y]=1;

 72                 }

 73             }

 74         }

 75     }

 76     for(i=0;i<n;i++){

 77         for(j=0;j<m;j++)

 78             A[i*6+j][30]=ma[i][j];

 79     }

 80 }

 81 

 82 void gauss(int n)

 83 {

 84     int i,j,k;

 85     for(i=0;i<n;i++){

 86         if(!A[i][i]){

 87             for(j=i+1;j<n;j++){

 88                 if(A[j][i]){

 89                     for(k=i;k<=n;k++)swap(A[i][k],A[j][k]);

 90                     break;

 91                 }

 92             }

 93         }

 94         for(j=i+1;j<n;j++){

 95             if(A[j][i]){

 96                 for(k=i;k<=n;k++)

 97                     A[j][k]^=A[i][k];

 98             }

 99         }

100     }

101     for(i=n-1;i>=0;i--){

102         k=0;

103         for(j=i+1;j<n;j++)k^=A[i][j]*B[j];

104         B[i]=k^A[i][n];

105     }

106 }

107 

108 int main()

109 {

110  //   freopen("in.txt","r",stdin);

111     int i,j,ca=1;

112     scanf("%d",&T);

113     while(T--)

114     {

115         for(i=0;i<5;i++){

116             for(j=0;j<6;j++)

117                 scanf("%d",&ma[i][j]);

118         }

119         getA(5,6);

120 

121         gauss(30);

122 

123         printf("PUZZLE #%d\n",ca++);

124         for(i=0;i<5;i++){

125             printf("%d",B[i*6]);

126             for(j=1;j<6;j++)

127                 printf(" %d",B[i*6+j]);

128             putchar('\n');

129         }

130     }

131     return 0;

132 }

 

你可能感兴趣的:(extend)