[LeetCode] Reverse Bits 位操作

Reverse bits of a given 32 bits unsigned integer.

For example, given input 43261596 (represented in binary as 00000010100101000001111010011100), return 964176192 (represented in binary as00111001011110000010100101000000).

Follow up:
If this function is called many times, how would you optimize it?

Related problem: Reverse Integer

Credits:
Special thanks to @ts for adding this problem and creating all test cases.

 

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  Bit Manipulation

 

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　　遍历输入数的位，输出数反向添加，循环时候需要注意先移位后修改，反过来会错的。

 

#include<iostream>

using namespace std;



class Solution {

public:

    uint32_t reverseBits(uint32_t n) {

        uint32_t m=0;

        for(int i=0;i<32;i++){

            m<<=1;

            m = m|(n & 1);

            n>>=1;

        }

        return m;

    }

};



int main()

{

    uint32_t n = 1;

    Solution sol;

    cout<<sol.reverseBits(n)<<endl;

    return 0;

}