[LeetCode]Single Number

Given an array of integers, every element appears twice except for one. Find that single one.

Note:
Your algorithm should have a linear runtime complexity. Could you implement it without using extra memory?

 

public class Solution {

    public int singleNumber(int[] A) {

        // Note: The Solution object is instantiated only once and is reused by each test case.

        int result = 0;

        if(A.length == 0)

            return 0;

        for(int i = 0;i<A.length;i++){

            result ^= A[i];

        }

        return result;

    }

}