ConcurrentHashMap内部排序的使用

业务中，我们经常会有队map进行排序的要求，如下将会详细讲解如何利用java8的lambda表达式实现map的内部排序。
首先，我们先构造一个person类：
public class Person {
private String addr;
private String age;

public String getAddr() {
    return addr;
}

public void setAddr(String addr) {
    this.addr = addr;
}

public String getAge() {
    return age;
}

public void setAge(String age) {
    this.age = age;
}

public Person(String addr, String age) {
    this.addr = addr;
    this.age = age;
}

@Override
public String toString() {
    return "Person{" +
            "addr='" + addr + '\'' +
            ", age='" + age + '\'' +
            '}';
}

}
测试，对map进行排序处理。
import com.ky.common.Person;

import java.util.*;
import java.util.concurrent.ConcurrentHashMap;
import java.util.stream.Collectors;
import java.util.stream.Stream;

import static java.util.Map.Entry.comparingByValue;
import static java.util.stream.Collectors.toMap;

public class Test {

public static void main(String[] args) {
    final ConcurrentHashMap map = new ConcurrentHashMap<>();
    Person p = new Person("河南周口","25");
    map.put("xiaofei", p);

    Person p1 = new Person("内蒙古","24");
    map.put("gq", p1);

    Person p2 = new Person("江苏扬州","22");
    map.put("wangfeng", p2);

    Person p3 = new Person("安徽合肥","26");
    map.put("xiaowei", p3);
    //方法1
    final LinkedHashMap collect = map.entrySet().stream().sorted(comparingByValue(new Comparator() {
        @Override
        public int compare(Person o1, Person o2) {
            return Integer.valueOf(o1.getAge()).compareTo(Integer.valueOf(o2.getAge()));
        }
    })).collect(toMap(e -> e.getKey(), e -> e.getValue(), (e1, e2) -> e2, LinkedHashMap::new));

    //方法2
    ConcurrentHashMap collect1 = map.entrySet().stream().sorted(new Comparator>() {
        @Override
        public int compare(Map.Entry o1, Map.Entry o2) {
            return Integer.valueOf(o1.getValue().getAge()).compareTo(Integer.valueOf(o2.getValue().getAge()));
        }
    }).collect(Collectors.toMap(e -> e.getKey(), e -> e.getValue(), (e1, e2) -> e2, ConcurrentHashMap::new));

    //方法3
    Stream> st = map.entrySet().stream();
    Comparator> com=new Comparator>() {
        @Override
        public int compare(Map.Entry o1, Map.Entry o2) {
            return Integer.valueOf(o1.getValue().getAge()).compareTo(Integer.valueOf(o2.getValue().getAge()));
        }
    };
    st.sorted(com).forEachOrdered(e->map.put(e.getKey(),e.getValue()));

//方法4

stream.sorted(Comparator.comparingInt(Map.Entry::getValue)).collect(Collectors.toMap(Map.Entry::getKey,
Map.Entry::getValue,(e1, e2)->e2, ConcurrentHashMap::new));

map.entrySet().stream().sorted(Comparator.comparing(Map.Entry::getValue)).forEach(System.out::println);

    final Collection values = collect.values();
    System.out.println(values);
}

}