统计文件中单词个数

#代码实现：

#coding = utf-8

import re

pattern = re.compile(r"[a-zA-Z]+")

count = 0

with open("e:\\python\\1129\\a.txt","r") as fp:

    for line in fp:

        s=[]

        if pattern.findall(line):

            print(pattern.findall(line))

            s=pattern.findall(line)

            count+=len(s)

print(count)

输出结果：

E:\python\1130>python 5.py

['Word']

['I', 'am', 'murphy']

['and', 'you']

['hi']

['murphy']

8

另外一个例子:写一个函数，其中用正则验证密码的强度

#coding = utf-8

import re

password = input("请输入6位密码:")

pattern =re.compile(r"\d+|\w+|\d+\w+|\w+\[!@#$%^&*]+")

check_password=pattern.findall(password)

if check_password:

    for i in check_password:

        if i.isdigit():

            print("密码强度:弱",str(check_password))

        elif i.isalpha():

            print("密码强度:中",str(check_password))

        elif i.isalnum():

            print("密码强度:强",str(check_password))

输出结果：

E:\python\1130>python 6.py

请输入6位密码,退出请输入q:123456

密码强度:弱 ['123456']