LeetCode Find Minimum In Rotated Sorted Array II

class Solution {

public:

    int findMin(vector<int> &num) {

        int L = 0, R = num.size() - 1;

        while (L < R && num[L] >= num[R]) {

            int mid= (L+R)/2;

            if (num[mid] > num[R]) {

                L = mid + 1;

            } else if (num[mid] < num[R]){

                R = mid;

            } else {

                L++;

            }

        }

        return num[L];

    }

};

Follow up for "Find Minimum in Rotated Sorted Array":
What if duplicates are allowed?

Would this affect the run-time complexity? How and why?

Suppose a sorted array is rotated at some pivot unknown to you beforehand.

(i.e., 0 1 2 4 5 6 7 might become 4 5 6 7 0 1 2).

Find the minimum element.

The array may contain duplicates.