Codeforces Round #296 (Div. 1) B. Clique Problem 贪心

B. Clique Problem

time limit per test

2 seconds

memory limit per test

256 megabytes

input

standard input

output

standard output

The clique problem is one of the most well-known NP-complete problems. Under some simplification it can be formulated as follows. Consider an undirected graph G. It is required to find a subset of vertices C of the maximum size such that any two of them are connected by an edge in graph G. Sounds simple, doesn't it? Nobody yet knows an algorithm that finds a solution to this problem in polynomial time of the size of the graph. However, as with many other NP-complete problems, the clique problem is easier if you consider a specific type of a graph.

Consider n distinct points on a line. Let the i-th point have the coordinate x_i and weight w_i. Let's form graph G, whose vertices are these points and edges connect exactly the pairs of points (i, j), such that the distance between them is not less than the sum of their weights, or more formally: |x_i - x_j| ≥ w_i + w_j.

Find the size of the maximum clique in such graph.

Input

The first line contains the integer n (1 ≤ n ≤ 200 000) — the number of points.

Each of the next n lines contains two numbers x_i, w_i (0 ≤ x_i ≤ 10⁹, 1 ≤ w_i ≤ 10⁹) — the coordinate and the weight of a point. All x_i are different.

Output

Print a single number — the number of vertexes in the maximum clique of the given graph.

Sample test(s)

Input

4
2 3
3 1
6 1
0 2

Output

3

If you happen to know how to solve this problem without using the specific properties of the graph formulated in the problem statement, then you are able to get a prize of one million dollars!

The picture for the sample test.

思路
排序，然后贪心，然后乱搞，类似于区间覆盖问题……

代码

//qscqesze

#include <cstdio>

#include <cmath>

#include <cstring>

#include <ctime>

#include <iostream>

#include <algorithm>

#include <set>

#include <vector>

#include <sstream>

#include <queue>

#include <typeinfo>

#include <fstream>

#include <map>

typedef long long ll;

using namespace std;

//freopen("D.in","r",stdin);

//freopen("D.out","w",stdout);

#define sspeed ios_base::sync_with_stdio(0);cin.tie(0)

#define maxn 200001

#define mod 10007

#define eps 1e-9

const int inf=0x7fffffff;   //无限大

/*

inline ll read()

{

    int x=0,f=1;char ch=getchar();

    while(ch<'0'||ch>'9'){if(ch=='-')f=-1;ch=getchar();}

    while(ch>='0'&&ch<='9'){x=x*10+ch-'0';ch=getchar();}

    return x*f;

}

*/

//**************************************************************************************



struct node

{

    int x,y;

};



node a[maxn];

bool cmp(node aa,node bb)

{

    if(aa.x==bb.x)

        return aa.y<bb.y;

    return aa.x<bb.x;

}

int main()

{

    int n,aa,bb;

    cin>>n;

    for(int i=0;i<n;i++)

    {

        scanf("%d%d",&aa,&bb);

        a[i].x=aa+bb;

        a[i].y=aa-bb;

    }

    sort(a,a+n,cmp);

    int l=-inf;

    int ans=0;

    for(int i=0;i<n;i++)

    {

        if(a[i].y>=l)

        {

            l=a[i].x;

            ans++;

        }

    }

    cout<<ans<<endl;

}