PAT 1042 Shuffling Machine
1042 Shuffling Machine
Shuffling is a procedure used to randomize a deck of playing cards. Because standard shuffling techniques are seen as weak, and in order to avoid "inside jobs" where employees collaborate with gamblers by performing inadequate shuffles, many casinos employ automatic shuffling machines. Your task is to simulate a shuffling machine.
The machine shuffles a deck of 54 cards according to a given random order and repeats for a given number of times. It is assumed that the initial status of a card deck is in the following order:
S1, S2, ..., S13,
H1, H2, ..., H13,
C1, C2, ..., C13,
D1, D2, ..., D13,
J1, J2
where "S" stands for "Spade", "H" for "Heart", "C" for "Club", "D" for "Diamond", and "J" for "Joker". A given order is a permutation of distinct integers in [1, 54]. If the number at the i-th position is j, it means to move the card from position i to position j. For example, suppose we only have 5 cards: S3, H5, C1, D13 and J2. Given a shuffling order {4, 2, 5, 3, 1}, the result will be: J2, H5, D13, S3, C1. If we are to repeat the shuffling again, the result will be: C1, H5, S3, J2, D13.
Input Specification:
Each input file contains one test case. For each case, the first line contains a positive integer K (≤20) which is the number of repeat times. Then the next line contains the given order. All the numbers in a line are separated by a space.
Output Specification:
For each test case, print the shuffling results in one line. All the cards are separated by a space, and there must be no extra space at the end of the line.
Sample Input:
2
36 52 37 38 3 39 40 53 54 41 11 12 13 42 43 44 2 4 23 24 25 26 27 6 7 8 48 49 50 51 9 10 14 15 16 5 17 18 19 1 20 21 22 28 29 30 31 32 33 34 35 45 46 47
Sample Output:
S7 C11 C10 C12 S1 H7 H8 H9 D8 D9 S11 S12 S13 D10 D11 D12 S3 S4 S6 S10 H1 H2 C13 D2 D3 D4 H6总结：这题目真的无语了，为什么不能先把所有的牌存下来，然后进行操作呢，就是要先进行操作在打印出来呢...
自己写的代码（AC不了）：
题目的大意：将对应位置的牌放在指定的位置上
#include
#include
using namespace std;
int main(){
int k;
int a[54];
char b[54][5]={"S1","S2","S3","S4","S5","S6","S7","S8","S9","S10","S11","S12","S13",
"H1","H2","H3","H4","H5","H6","H7","H8","H9","H10","H11","H12","H13",
"C1","C2","C3","C4","C5","C6","C7","C8","C9","C10","C11","C12","C13",
"D1","D2","D3","D4","D5","D6","D7","D8","D9","D10","D11","12","D13",
"J1","J2"};
cin >> k;
for(int i=0;i<54;i++) scanf("%d",&a[i]);
for(int i=0;i AC代码：
#include
using namespace std;
int main() {
int cnt;
scanf("%d", &cnt);
int start[55], end[55], scan[55];
for(int i = 1; i < 55; i++) {
scanf("%d", &scan[i]);
end[i] = i;
}
for(int i = 0; i < cnt; i++) {
for(int j = 1; j < 55; j++)
start[j] = end[j];
for(int k = 1; k < 55; k++)
end[scan[k]] = start[k];
}
char c[6] = {"SHCDJ"};
for(int i = 1; i < 55; i++) {
end[i] = end[i] - 1;
printf("%c%d", c[end[i]/13], end[i]%13+1);
if(i != 54) printf(" ");
}
return 0;
} 好好学习，天天向上！
我要考研！