python numpy pandas 题目_Python中 Pandas 50题冲关

参考资料 | 100-pandas-puzzles - GitHub | Pandas 百题大冲关

基本操作导入 Pandas 库并简写为 pd,并输出版本号

import pandas as pd

pd.__version__从列表创建 Seriesarr = [0, 1, 2, 3, 4]

df = pd.Series(arr) # 如果不指定索引,则默认从 0 开始

df从字典创建 Series

d = {'a':1,'b':2,'c':3,'d':4,'e':5}

df = pd.Series(d)

df从 NumPy 数组创建 DataFramedates = pd.date_range('today',periods=6) # 定义时间序列作为 index

num_arr = np.random.randn(6,4) # 传入 numpy 随机数组

columns = ['A','B','C','D'] # 将列表作为列名

df = pd.DataFrame(num_arr, index = dates, columns = columns)

df从CSV中创建 DataFrame,分隔符为“;”,编码格式为gbk

df = pd.read_csv('test.csv', encoding='gbk, sep=';')从字典对象创建DataFrame,并设置索引import numpy as np

data = {'animal': ['cat', 'cat', 'snake', 'dog', 'dog', 'cat', 'snake', 'cat', 'dog', 'dog'],

'age': [2.5, 3, 0.5, np.nan, 5, 2, 4.5, np.nan, 7, 3],

'visits': [1, 3, 2, 3, 2, 3, 1, 1, 2, 1],

'priority': ['yes', 'yes', 'no', 'yes', 'no', 'no', 'no', 'yes', 'no', 'no']}

labels = ['a', 'b', 'c', 'd', 'e', 'f', 'g', 'h', 'i', 'j']

df = pd.DataFrame(data, index=labels)

df显示df的基础信息,包括行的数量;列名;每一列值的数量、类型df.info()

# 方法二

# df.describe()展示df的前3行

df.iloc[:3]

# 方法二

#df.head(3)取出df的animal和age列df.loc[:, ['animal', 'age']]

# 方法二

# df[['animal', 'age']]取出索引为[3, 4, 8]行的animal和age列

df.loc[df.index[[3, 4, 8]], ['animal', 'age']]取出age值大于3的行df[df['age'] > 3]取出age值缺失的行

df[df['age'].isnull()]取出age在2,4间的行(不含)df[(df['age']>2) & (df['age']>4)]

# 方法二

# df[df['age'].between(2, 4)]f行的age改为1.5

df.loc['f', 'age'] = 1.5计算visits的总和df['visits'].sum()计算每个不同种类animal的age的平均数

df.groupby('animal')['age'].mean()在df中插入新行k,然后删除该行#插入

df.loc['k'] = [5.5, 'dog', 'no', 2]

# 删除

df = df.drop('k')

df计算df中每个种类animal的数量

df['animal'].value_counts()先按age降序排列,后按visits升序排列df.sort_values(by=['age', 'visits'], ascending=[False, True])将priority列中的yes, no替换为布尔值True, False

df['priority'] = df['priority'].map({'yes': True, 'no': False})

df将animal列中的snake替换为pythondf['animal'] = df['animal'].replace('snake', 'python')

df对每种animal的每种不同数量visits,计算平均age,即,返回一个表格,行是aniaml种类,列是visits数量,表格值是行动物种类列访客数量的平均年龄

df.pivot_table(index='animal', columns='visits', values='age', aggfunc='mean')

进阶操作有一列整数列A的DatraFrame,删除数值重复的行df = pd.DataFrame({'A': [1, 2, 2, 3, 4, 5, 5, 5, 6, 7, 7]})

print(df)

df1 = df.loc[df['A'].shift() != df['A']]

# 方法二

# df1 = df.drop_duplicates(subset='A')

print(df1)一个全数值DatraFrame,每个数字减去该行的平均数

df = pd.DataFrame(np.random.random(size=(5, 3)))

print(df)

df1 = df.sub(df.mean(axis=1), axis=0)

print(df1)一个有5列的DataFrame,求哪一列的和最小df = pd.DataFrame(np.random.random(size=(5, 5)), columns=list('abcde'))

print(df)

df.sum().idxmin()给定DataFrame,求A列每个值的前3的B的值的和

df = pd.DataFrame({'A': list('aaabbcaabcccbbc'),

'B': [12,345,3,1,45,14,4,52,54,23,235,21,57,3,87]})

print(df)

df1 = df.groupby('A')['B'].nlargest(3).sum(level=0)

print(df1)给定DataFrame,有列A, B,A的值在1-100(含),对A列每10步长,求对应的B的和df = pd.DataFrame({'A': [1,2,11,11,33,34,35,40,79,99],

'B': [1,2,11,11,33,34,35,40,79,99]})

print(df)

df1 = df.groupby(pd.cut(df['A'], np.arange(0, 101, 10)))['B'].sum()

print(df1)给定DataFrame,计算每个元素至左边最近的0(或者至开头)的距离,生成新列y

df = pd.DataFrame({'X': [7, 2, 0, 3, 4, 2, 5, 0, 3, 4]})

izero = np.r_[-1, (df['X'] == 0).to_numpy().nonzero()[0]] # 标记0的位置

idx = np.arange(len(df))

df['Y'] = idx - izero[np.searchsorted(izero - 1, idx) - 1]

print(df)

# 方法二

# x = (df['X'] != 0).cumsum()

# y = x != x.shift()

# df['Y'] = y.groupby((y != y.shift()).cumsum()).cumsum()

# 方法三

# df['Y'] = df.groupby((df['X'] == 0).cumsum()).cumcount()

#first_zero_idx = (df['X'] == 0).idxmax()

# df['Y'].iloc[0:first_zero_idx] += 1一个全数值的DataFrame,返回最大3个值的坐标df = pd.DataFrame(np.random.random(size=(5, 3)))

print(df)

df.unstack().sort_values()[-3:].index.tolist()给定DataFrame,将负值代替为同组的平均值

df = pd.DataFrame({'grps': list('aaabbcaabcccbbc'),

'vals': [-12,345,3,1,45,14,4,-52,54,23,-235,21,57,3,87]})

print(df)

def replace(group):

mask = group<0

group[mask] = group[~mask].mean()

return group

df['vals'] = df.groupby(['grps'])['vals'].transform(replace)

print(df)计算3位滑动窗口的平均值,忽略NANdf = pd.DataFrame({'group': list('aabbabbbabab'),

'value': [1, 2, 3, np.nan, 2, 3, np.nan, 1, 7, 3, np.nan, 8]})

print(df)

g1 = df.groupby(['group'])['value']

g2 = df.fillna(0).groupby(['group'])['value']

s = g2.rolling(3, min_periods=1).sum() / g1.rolling(3, min_periods=1).count()

s.reset_index(level=0, drop=True).sort_index()

Series 和 Datetime索引创建Series s,将2015所有工作日作为随机值的索引

dti = pd.date_range(start='2015-01-01', end='2015-12-31', freq='B')

s = pd.Series(np.random.rand(len(dti)), index=dti)

s.head(10)所有礼拜三的值求和s[s.index.weekday == 2].sum()求每个自然月的平均数

s.resample('M').mean()每连续4个月为一组,求最大值所在的日期s.groupby(pd.Grouper(freq='4M')).idxmax()创建2015-2016每月第三个星期四的序列

pd.date_range('2015-01-01', '2016-12-31', freq='WOM-3THU')

数据清洗df = pd.DataFrame({'From_To': ['LoNDon_paris', 'MAdrid_miLAN', 'londON_StockhOlm',

'Budapest_PaRis', 'Brussels_londOn'],

'FlightNumber': [10045, np.nan, 10065, np.nan, 10085],

'RecentDelays': [[23, 47], [], [24, 43, 87], [13], [67, 32]],

'Airline': ['KLM(!)', ' (12)', '(British Airways. )',

'12. Air France', ''Swiss Air'']})

dfFlightNumber列中有些值缺失了,他们本来应该是每一行增加10,填充缺失的数值,并且令数据类型为整数

df['FlightNumber'] = df['FlightNumber'].interpolate().astype(int)

df将From_To列从_分开,分成From, To两列,并删除原始列temp = df.From_To.str.split('_', expand=True)

temp.columns = ['From', 'To']

df = df.join(temp)

df = df.drop('From_To', axis=1)

df将From, To大小写统一首字母大写其余小写

df['From'] = df['From'].str.capitalize()

df['To'] = df['To'].str.capitalize()

dfAirline列,有一些多余的标点符号,需要提取出正确的航司名称。举例:'(British Airways. )' 应该改为 'British Airways'.df['Airline'] = df['Airline'].str.extract('([a-zA-Z\s]+)', expand=False).str.strip()

dfAirline列,数据被以列表的形式录入,但是我们希望每个数字被录入成单独一列,delay_1, delay_2, ...没有的用NAN替代。

delays = df['RecentDelays'].apply(pd.Series)

delays.columns = ['delay_{}'.format(n) for n in range(1, len(delays.columns)+1)]

df = df.drop('RecentDelays', axis=1).join(delays)

df

层次化索引用 letters = ['A', 'B', 'C']和 numbers = list(range(10))的组合作为系列随机值的层次化索引letters = ['A', 'B', 'C']

numbers = list(range(4))

mi = pd.MultiIndex.from_product([letters, numbers])

s = pd.Series(np.random.rand(12), index=mi)

s检查s是否是字典顺序排序的

s.index.is_lexsorted()

# 方法二

# s.index.lexsort_depth == s.index.nlevels选择二级索引为1, 3的行s.loc[:, [1, 3]]对s进行切片操作,取一级索引至B,二级索引从2开始到最后

s.loc[pd.IndexSlice[:'B', 2:]]

# 方法二

# s.loc[slice(None, 'B'), slice(2, None)]

46.计算每个一级索引的和(A, B, C每一个的和)s.sum(level=0)

#方法二

#s.unstack().sum(axis=0)交换索引等级,新的Series是字典顺序吗?不是的话请排序

new_s = s.swaplevel(0, 1)

print(new_s)

print(new_s.index.is_lexsorted())

new_s = new_s.sort_index()

print(new_s)

可视化import matplotlib.pyplot as plt

df = pd.DataFrame({'xs':[1,5,2,8,1], 'ys':[4,2,1,9,6]})

plt.style.use('ggplot')画出df的散点图

df.plot.scatter('xs', 'ys', color = 'black', marker = 'x')可视化指定4维DataFramedf = pd.DataFrame({'productivity':[5,2,3,1,4,5,6,7,8,3,4,8,9],

'hours_in' :[1,9,6,5,3,9,2,9,1,7,4,2,2],

'happiness' :[2,1,3,2,3,1,2,3,1,2,2,1,3],

'caffienated' :[0,0,1,1,0,0,0,0,1,1,0,1,0]})

df.plot.scatter('hours_in', 'productivity', s = df.happiness * 100, c = df.caffienated)在同一个图中可视化2组数据,共用X轴,但y轴不同

df = pd.DataFrame({'revenue':[57,68,63,71,72,90,80,62,59,51,47,52],

'advertising':[2.1,1.9,2.7,3.0,3.6,3.2,2.7,2.4,1.8,1.6,1.3,1.9],

'month':range(12)})

ax = df.plot.bar('month', 'revenue', color = 'green')

df.plot.line('month', 'advertising', secondary_y = True, ax = ax)

ax.set_xlim((-1,12));

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