Java语言编写Tic-Tac-Toe游戏(含注解)

此程序中用了五个方法,play1()和play2()分别用于接收用户12的输入然后更新棋盘,deal()用于判断用户的输入是否有效,print()用于在用户操作后打印棋盘格,judge()用于判断是否有某一种棋子连成一行,即判断游戏是否要继续进行。

代码如下:

import java.util.*;

public class tic-tac-toe {
    public static void main(String[] args) {
        System.out.println("Let's play tic-tac-toe");
        // 构建一个3*3的二维数组(初始棋盘)
        char[][] checkerboard = new char[3][3];
        Scanner in = new Scanner(System.in);
        System.out.println("Who want to first?(please enter player1 or player2)");
        String first = in.next();
        if(first.equals("player1")){
            int round = 1;
            boolean judge = false;
            while(judge == false){
                if(round%2 == 1){
                    checkerboard = play1(checkerboard);
                    print(checkerboard);
                    if(judge(checkerboard)==true){
                        break;
                    }
                    round ++;
                }else{
                    checkerboard = play2(checkerboard);
                    print(checkerboard);
                    if(judge(checkerboard)==true){
                        break;
                    }
                    round++;
                }
            }
        }else {
            int round = 2;
            boolean judge = false;
            while (judge == false) {
                if (round % 2 == 1) {
                    checkerboard = play1(checkerboard);
                    print(checkerboard);
                    if (judge(checkerboard) == true) {
                        break;
                    }
                    round++;
                } else {
                    checkerboard = play2(checkerboard);
                    print(checkerboard);
                    if (judge(checkerboard) == true) {
                        break;
                    }
                    round++;
                }
            }
        }
    }

    // 方法print()用于打印操作后的棋盘格
    public static void print(char[][] checkerboard){
        System.out.println("-------------");
        for(int i = 0;i <= 2; i++){
            System.out.print("|");
            for(int j = 0;j <= 2; j++){
                if(checkerboard[i][j]=='X'||checkerboard[i][j]=='O') {
                    System.out.print(" "+checkerboard[i][j]+" ");
                    System.out.print("|");
                }else{
                    System.out.print("   ");
                    System.out.print("|");
                }
            }
            System.out.println();
            System.out.println("-------------");
        }
    }

    // 方法play1用于处理用户1输入的选择,此处设置用户1的棋子为字符'X'
    public static char[][] play1(char[][] checkerboard){
        Scanner in = new Scanner(System.in);
        System.out.print("Player1's move?(Enter the number of rows and columns, separated by spaces.)");
        int line = in.nextInt();
        int row = in.nextInt();
        while(deal(line,row,checkerboard) == false){
            System.out.print("Player1's move?(Enter the number of rows and columns, separated by spaces.)");
            line = in.nextInt();
            row = in.nextInt();
        }
        checkerboard[line-1][row-1] = 'X';
        return checkerboard;
    }

    // 方法play2用于处理用户1输入的选择,此处设置用户1的棋子为字符'O'
    public static char[][] play2(char[][] checkerboard){
        Scanner in = new Scanner(System.in);
        System.out.print("Player2's move?(Enter the number of rows and columns, separated by spaces.)");
        int line = in.nextInt();
        int row = in.nextInt();
        while(deal(line,row,checkerboard) == false){
            System.out.print("Player2's move?(Enter the number of rows and columns, separated by spaces.)");
            line = in.nextInt();
            row = in.nextInt();
        }
        checkerboard[line-1][row-1] = 'O';
        return checkerboard;
    }

    // 方法deal用于处理用户的输入,检测输入是否有效
    public static boolean deal(int line,int row,char[][] checkerboard){
        if(line == 0 || line > 3 || row == 0 || row > 3){  // 输入行列数不在范围内的情况
            System.out.println("Please enter a valid number of rows and columns.");
            return false;
        }else if(checkerboard[line-1][row-1]=='X' || checkerboard[line-1][row-1]=='O'){  // 输入位置已有棋子的情况
            System.out.println("There is already a piece, please re-enter your choice.");
            return false;
        }else{
            return true;
        }
    }

    // 方法judge用于判断是否有三个棋子连成一行
    public static boolean judge(char[][] checkerboard){
        // 判断一行上是否有棋子相连
        for (int i = 0; i <= 2; i++){
            int continuity_x = 0;
            int continuity_o = 0;
            for (int j = 0; j <= 2;j++){
                if (checkerboard[i][j] == 'X'){
                    continuity_x++;
                }else if (checkerboard[i][j] == 'O'){
                    continuity_o++;
                }
            }
            if(continuity_x == 3){
                System.out.println("Player1 wins!");
                return true;
            }else if(continuity_o == 3){
                System.out.println("Player2 wins!");
                return true;
            }
        }
        // 判断一列上是否有棋子相连
        for (int j = 0; j <= 2; j++){
            int continuity_x = 0;
            int continuity_o = 0;
            for (int i = 0; i <= 2;i++){
                if (checkerboard[i][j] == 'X'){
                    continuity_x++;
                }else if (checkerboard[i][j] == 'O'){
                    continuity_o++;
                }
            }
            if(continuity_x == 3){
                System.out.println("Player1 wins!");
                return true;
            }else if(continuity_o == 3){
                System.out.println("Player2 wins!");
                return true;
            }
        }

        // 判断对角线上是否有棋子相连
        if(checkerboard[0][0]=='X'&checkerboard[1][1]=='X'&checkerboard[2][2]=='X'){
            System.out.println("Player1 wins!");
            return true;
        }else if(checkerboard[0][0]=='O'&checkerboard[1][1]=='O'&checkerboard[2][2]=='O'){
            System.out.println("Player2 wins!");
            return true;
        }
        return false;
    }
}

运行结果测试:在测试多种可能后,会发现有一种可能双方的棋子都没有连成一行Java语言编写Tic-Tac-Toe游戏(含注解)_第1张图片

 所以在judge方法中我添加了对这一类情况的判断,修改后代码如下:

import java.util.*;

public class tic_tac_toe {
    public static void main(String[] args) {
        System.out.println("Let's play tic-tac-toe");
        // 构建一个3*3的二维数组(初始棋盘)
        char[][] checkerboard = new char[3][3];
        Scanner in = new Scanner(System.in);
        System.out.println("Who want to first?(please enter player1 or player2)");
        String first = in.next();
        if(first.equals("player1")){
            int round = 1;
            boolean judge = false;
            while(judge == false){
                if(round%2 == 1){
                    checkerboard = play1(checkerboard);
                    print(checkerboard);
                    if(judge(checkerboard)==true){
                        break;
                    }
                    round ++;
                }else{
                    checkerboard = play2(checkerboard);
                    print(checkerboard);
                    if(judge(checkerboard)==true){
                        break;
                    }
                    round++;
                }
            }
        }else {
            int round = 2;
            boolean judge = false;
            while (judge == false) {
                if (round % 2 == 1) {
                    checkerboard = play1(checkerboard);
                    print(checkerboard);
                    if (judge(checkerboard) == true) {
                        break;
                    }
                    round++;
                } else {
                    checkerboard = play2(checkerboard);
                    print(checkerboard);
                    if (judge(checkerboard) == true) {
                        break;
                    }
                    round++;
                }
            }
        }
    }

    // 方法print()用于打印操作后的棋盘格
    public static void print(char[][] checkerboard){
        System.out.println("-------------");
        for(int i = 0;i <= 2; i++){
            System.out.print("|");
            for(int j = 0;j <= 2; j++){
                if(checkerboard[i][j]=='X'||checkerboard[i][j]=='O') {
                    System.out.print(" "+checkerboard[i][j]+" ");
                    System.out.print("|");
                }else{
                    System.out.print("   ");
                    System.out.print("|");
                }
            }
            System.out.println();
            System.out.println("-------------");
        }
    }

    // 方法play1用于处理用户1输入的选择,此处设置用户1的棋子为字符'X'
    public static char[][] play1(char[][] checkerboard){
        Scanner in = new Scanner(System.in);
        System.out.print("Player1's move?(Enter the number of rows and columns, separated by spaces.)");
        int line = in.nextInt();
        int row = in.nextInt();
        while(deal(line,row,checkerboard) == false){
            System.out.print("Player1's move?(Enter the number of rows and columns, separated by spaces.)");
            line = in.nextInt();
            row = in.nextInt();
        }
        checkerboard[line-1][row-1] = 'X';
        return checkerboard;
    }

    // 方法play2用于处理用户1输入的选择,此处设置用户1的棋子为字符'O'
    public static char[][] play2(char[][] checkerboard){
        Scanner in = new Scanner(System.in);
        System.out.print("Player2's move?(Enter the number of rows and columns, separated by spaces.)");
        int line = in.nextInt();
        int row = in.nextInt();
        while(deal(line,row,checkerboard) == false){
            System.out.print("Player2's move?(Enter the number of rows and columns, separated by spaces.)");
            line = in.nextInt();
            row = in.nextInt();
        }
        checkerboard[line-1][row-1] = 'O';
        return checkerboard;
    }

    // 方法deal用于处理用户的输入,检测输入是否有效
    public static boolean deal(int line,int row,char[][] checkerboard){
        if(line == 0 || line > 3 || row == 0 || row > 3){  // 输入行列数不在范围内的情况
            System.out.println("Please enter a valid number of rows and columns.");
            return false;
        }else if(checkerboard[line-1][row-1]=='X' || checkerboard[line-1][row-1]=='O'){  // 输入位置已有棋子的情况
            System.out.println("There is already a piece, please re-enter your choice.");
            return false;
        }else{
            return true;
        }
    }

    // 方法judge用于判断是否有三个棋子连成一行
    public static boolean judge(char[][] checkerboard){
        // 判断一行上是否有棋子相连
        for (int i = 0; i <= 2; i++){
            int continuity_x = 0;
            int continuity_o = 0;
            for (int j = 0; j <= 2;j++){
                if (checkerboard[i][j] == 'X'){
                    continuity_x++;
                }else if (checkerboard[i][j] == 'O'){
                    continuity_o++;
                }
            }
            if(continuity_x == 3){
                System.out.println("Player1 wins!");
                return true;
            }else if(continuity_o == 3){
                System.out.println("Player2 wins!");
                return true;
            }
        }
        // 判断一列上是否有棋子相连
        for (int j = 0; j <= 2; j++){
            int continuity_x = 0;
            int continuity_o = 0;
            for (int i = 0; i <= 2;i++){
                if (checkerboard[i][j] == 'X'){
                    continuity_x++;
                }else if (checkerboard[i][j] == 'O'){
                    continuity_o++;
                }
            }
            if(continuity_x == 3){
                System.out.println("Player1 wins!");
                return true;
            }else if(continuity_o == 3){
                System.out.println("Player2 wins!");
                return true;
            }
        }

        // 判断对角线上是否有棋子相连
        if(checkerboard[0][0]=='X'&checkerboard[1][1]=='X'&checkerboard[2][2]=='X'){
            System.out.println("Player1 wins!");
            return true;
        }else if(checkerboard[0][0]=='O'&checkerboard[1][1]=='O'&checkerboard[2][2]=='O'){
            System.out.println("Player2 wins!");
            return true;
        }
        // 判断棋盘是否已满
        for (int j = 0; j <= 2; j++){
            int num = 0;
            for (int i = 0; i <= 2;i++){
                if (checkerboard[i][j] == 'X'|| checkerboard[i][j] == 'O'){
                    num++;
                }
            }
            if(num == 9){
                System.out.println("tie");
                return true;
            }
        }
        return false;
    }
}

运行测试:

Java语言编写Tic-Tac-Toe游戏(含注解)_第2张图片

Java语言编写Tic-Tac-Toe游戏(含注解)_第3张图片 

 

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