(3)Decide_1判定表达式的3个定义:
Check if the operation is Add判定1:iVar3 == "Add"
Check if the Operation is Subtract判定2:iVar3 == "Sub"
Else:没有代码
(4)Check if the operation is Add判定1里面Call Add Method表达式形状代码
iResult = mathVar.Add(iVar1,iVar2);
(5)Check if the Operation is Subtract判定2里面Call Subtract Method表达式代码
iResult = mathVar.Subtract(iVar1,iVar2);
(6)中止形状Terminate_1里面"ERROR";
(7)Expression_2表达式代码:System.Diagnostics.Debug.WriteLine(iResult);
(8)构造消息形状ConstructMessage_1消息mOutgoing用来构造输出的消息
(9)消息赋值形状MessageAssignment_1编写代码mOutgoing=MathLibrary_test112.Helper.ConstructDoc(iResult);
(10)发送形状Send_1 消息mOutgoing
(11)激活Receive_1形状
冒泡排序
public static void sort(Integer[] param) {
for (int i = param.length - 1; i > 0; i--) {
for (int j = 0; j < i; j++) {
int current = param[j];
int next = param[j + 1];
方法一:
public class Zhidao {
public static void main(String args[]) {
String s = "sdf灭礌 kjl d{';\fdsjlk是";
int n=0;
for(int i=0; i<s.length(); i++) {
n = (int)s.charAt(i);
if((
IF OBJECT_ID('tempdb..#ABC') is not null
drop table tempdb..#ABC
create table #ABC
(
PATHNAME NVARCHAR(50)
)
insert into #ABC
SELECT N'/ABCDEFGHI'
UNION ALL SELECT N'/ABCDGAFGASASSDFA'
UNION ALL
http://www.sdn.sap.com/irj/boc/business-objects-for-sap-faq
Besides, I care that how to integrate tightly.
By the way, for BW consultants, please just focus on Query Designer which i
结构
继承关系
public static final class Manifest.permission_group extends Object
java.lang.Object
android. Manifest.permission_group 常量
ACCOUNTS 直接通过统计管理器访问管理的统计
COST_MONEY可以用来让用户花钱但不需要通过与他们直接牵涉的权限
D