from random import choice
l = [1, 2, 3, 4, 5, 6, 7, 8, 9]
print(choice(l))
choice(seq): Choose a random element from a non-empty sequence
from random import sample
l = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]
print(sample(l, 5)) # 随机抽取5个元素
'''
[5, 10, 1, 4, 2]
'''
sample(seq): Chooses k unique random elements from a population sequence or set.
import numpy as np
l = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]
index = np.random.randint(0, len(l), size=5)
print([l[i] for i in index])
'''
[9, 9, 4, 3, 4]
'''
randint(low, high=None, size=None): Return random integers from
low
(inclusive) tohigh
(exclusive).
numpy.random.choice(a, size=None, replace=True, p=None): 从一维 数组
a
中选出size
个元素,a
中每个元素被选中的概率由一维数组p
定义
replace=True
: 可以从a
中反复选取同一个元素
replace=False
:a
中同一个元素只能被选取一次
import numpy as np
array = list(range(10))
repeat = np.random.choice(array, size=5, replace=True)
print(f"replace=True的情况:{repeat}")
no_repeat = np.random.choice(array, size=5, replace=False)
print(f"replace=False的情况:{no_repeat}")
'''
replace=True的情况:[6 2 9 1 6]
replace=False的情况:[1 4 7 2 0]
'''
1、python技巧——从list中随机抽取元素的方法
2、What does replacement mean in numpy.random.choice?