C++制作“简单”小游戏

好久都没有更新这个系列的专栏了，我们来康康吧。

今天，我们用C++只做一个小游戏—2048小游戏。

或许，有人会说：这太没技术含量了，简直信手捏来！

那么，用easyx呢？

台下观众：

接下来，废话不多说，咱们直接先看一下项目截图：

 

然后代码伺候：

#include 
#include 
#include 
#include 
#include 
#include 

using namespace std;

const COLORREF BGC = RGB(250, 248, 239);
int score, best, a[5][5], b[5][5];		
bool mov[5][5];							

void init()
{
	setbkcolor(BGC);
	setbkmode(TRANSPARENT);
	score = 0;
	memset(a, 0, sizeof(a));
	int x1 = rand() % 4 + 1, y1 = rand() % 4 + 1, x2 = rand() % 4 + 1, y2 = rand() % 4 + 1;	// 随机生成两个初始点
	a[x1][y1] = a[x2][y2] = 2;				
}


void drawmap()
{
	BeginBatchDraw();
	cleardevice();
	settextcolor(RGB(119, 110, 101));
	settextstyle(50, 0, L"微软雅黑");
	outtextxy(10, 10, L"2048");
	settextstyle(20, 0, L"微软雅黑", 0, 0, 550, false, false, false);
	outtextxy(10, 65, L"Join the numbers and get to the 2048 tile!");

	setfillcolor(RGB(187, 173, 160));
	solidroundrect(200, 15, 290, 60, 5, 5);
	settextcolor(RGB(230, 220, 210));
	settextstyle(15, 0, L"微软雅黑", 0, 0, 600, false, false, false);
	outtextxy(230, 20, L"SCORE");
	wchar_t sc[10] = L"";
	swprintf_s(sc, L"%d", score);
	settextcolor(WHITE);
	settextstyle(25, 0, L"微软雅黑", 0, 0, 600, false, false, false);
	RECT r = { 200, 30, 290, 60 };
	drawtext(sc, &r, DT_CENTER | DT_VCENTER | DT_SINGLELINE);
	solidroundrect(295, 15, 385, 60, 5, 5);
	settextcolor(RGB(230, 220, 210));
	settextstyle(15, 0, L"微软雅黑", 0, 0, 600, false, false, false);
	outtextxy(330, 20, L"BEST");
	wchar_t bs[10] = L"";
	swprintf_s(bs, L"%d", best);
	settextcolor(WHITE);
	settextstyle(25, 0, L"微软雅黑", 0, 0, 600, false, false, false);
	r = { 295, 30, 385, 60 };
	drawtext(bs, &r, DT_CENTER | DT_VCENTER | DT_SINGLELINE);
	solidroundrect(10, 90, 390, 470, 5, 5);
	settextstyle(23, 0, L"微软雅黑");
	settextcolor(WHITE);
	for (int i = 1; i <= 4; i++)
		for (int j = 1; j <= 4; j++)
			if (a[i][j])	
			{
				setfillcolor(RGB((unsigned int)(BGC - 3 * (a[i][j] ^ 29)) % 256, (unsigned int)(BGC - 11 * (a[i][j] ^ 23)) % 256, (unsigned int)(BGC + 7 * (a[i][j] ^ 37)) % 256));
				solidroundrect(94 * j - 80, 94 * i, 94 * j + 10, 94 * i + 90, 5, 5);
				wchar_t num[10] = L"";
				swprintf_s(num, L"%d", a[i][j]);
				r = { 94 * j - 80, 94 * i, 94 * j + 10, 94 * i + 90 };
				drawtext(num, &r, DT_CENTER | DT_VCENTER | DT_SINGLELINE);
			}
	EndBatchDraw();
}

void move()
{
	memcpy(b, a, sizeof(a));		
	memset(mov, false, sizeof(mov));	
	char userkey = _getch();
	if (userkey == -32)
		userkey = -_getch();
	switch (userkey)
	{
	case 'w':
	case 'W':
	case -72:
		for (int j = 1; j <= 4; j++)
			for (int i = 2; i <= 4; i++)
			{
				if (!a[i][j])continue;
				int k = i;
				while (!a[k - 1][j] && k >= 2)
				{
					a[k - 1][j] = a[k][j];
					a[k][j] = 0;
					k--;
				}
				if (a[k][j] == a[k - 1][j] && !mov[k - 1][j])
				{
					a[k - 1][j] = 2 * a[k][j];
					a[k][j] = 0;
					mov[k - 1][j] = true;
					score += a[k - 1][j];
				}
			}
		break;
	case 's':
	case 'S':
	case -80:
		for (int j = 1; j <= 4; j++)
			for (int i = 3; i >= 1; i--)
			{
				if (!a[i][j])continue;
				int k = i;
				while (!a[k + 1][j] && k <= 3)
				{
					a[k + 1][j] = a[k][j];
					a[k][j] = 0;
					k++;
				}
				if (a[k][j] == a[k + 1][j] && !mov[k + 1][j])
				{
					a[k + 1][j] = 2 * a[k][j];
					a[k][j] = 0;
					mov[k + 1][j] = true;
					score += a[k + 1][j];
				}
			}
		break;
	case 'a':
	case 'A':
	case -75:
		for (int i = 1; i <= 4; i++)
			for (int j = 2; j <= 4; j++)
			{
				if (!a[i][j])continue;
				int k = j;
				while (!a[i][k - 1] && k >= 2)
				{
					a[i][k - 1] = a[i][k];
					a[i][k] = 0;
					k--;
				}
				if (a[i][k] == a[i][k - 1] && !mov[i][k - 1])
				{
					a[i][k - 1] = 2 * a[i][k];
					a[i][k] = 0;
					mov[i][k - 1] = true;
					score += a[i][k - 1];
				}
			}
		break;
	case 'd':
	case 'D':
	case -77:
		for (int i = 1; i <= 4; i++)
			for (int j = 3; j >= 1; j--)
			{
				if (!a[i][j])continue;
				int k = j;
				while (!a[i][k + 1] && k <= 3)
				{
					a[i][k + 1] = a[i][k];
					a[i][k] = 0;
					k++;
				}
				if (a[i][k] == a[i][k + 1] && !mov[i][k + 1])
				{
					a[i][k + 1] = 2 * a[i][k];
					a[i][k] = 0;
					mov[i][k + 1] = true;
					score += a[i][k + 1];
				}
			}
		break;
	}
	bool change = false;				
	for (int i = 1; i <= 4; i++)
		for (int j = 1; j <= 4; j++)
			if (a[i][j] != b[i][j])
			{
				change = true;
				break;
			}
	if (!change)
		return;					
	int x, y;
	do
	{
		x = rand() % 4 + 1;
		y = rand() % 4 + 1;
	} while (a[x][y]);
	int n = rand() % 6;
	if (n == 5)a[x][y] = 4;
	else a[x][y] = 2;
	best = max(best, score);
}

bool gameover()
{
	
	for (int i = 1; i <= 4; i++)
		for (int j = 1; j <= 4; j++)
			if (!a[i][j] || a[i][j] == a[i + 1][j] || a[i][j] == a[i - 1][j] || a[i][j] == a[i][j + 1] || a[i][j] == a[i][j - 1])return false;

	return true;
}

bool win()
{
	for (int i = 1; i <= 4; i++)
		for (int j = 1; j <= 4; j++)
			if (a[i][j] == 2048)return true;
	return false;
}

int main()
{
	bool ctn = true;					
	initgraph(400, 480);			
	srand((unsigned)time(NULL));
	while (ctn)
	{
		init();							
		drawmap();						
		int endmode = 0;				
		while (1)
		{
			move();						
			drawmap();					
			if (win())				
			{
				endmode = 1;
				break;
			}
			if (gameover())				
			{
				endmode = 2;
				break;
			}
		}
		int t;							
		if (endmode == 1)				
			t = MessageBox(0, L"You win!\n再来一局？", L"继续", MB_OKCANCEL);
		if (endmode == 2)			
			t = MessageBox(0, L"Game over!\n再来一局？", L"继续", MB_OKCANCEL);
		if (t == IDCANCEL)ctn = false;	
	}
	closegraph();						
	return 0;
}

咋样？是不是感觉飘飘然，自己有一点看不懂？

慢慢理解吧，后续，我也会出一些关于我发的这些游戏的解释帖子，欢迎大家关注我，等待以后我的：“音讯”。

今天的内容就是这样，下期再见！