使用python小程序查看班级健康码是否收齐，并返回未提交的人名

代码如下：

#Auther:ponny lee
#Time:2021/09/05,0005 19:25
#File:contrust_healthy_code.py
#IDE :PyCharm

import os
import json

diffs = []
def diff_file(path1, path2):
    fileName1 = set([_ for _ in os.listdir(path1)])
    name1 = []
    for i in fileName1:
        portion = os.path.splitext(i)  # 把文件名拆分为名字和后缀
        if portion[1] == ".jpg":
            name1.append(portion[0])
        if portion[1] == ".png":
            name1.append(portion[0])

    fileName2 = set([_ for _ in os.listdir(path2)])
    name2 = []
    for i in fileName2:
        portion = os.path.splitext(i)  # 把文件名拆分为名字和后缀
        if portion[1] == ".jpg":
            name2.append(portion[0])
        if portion[1] == ".png":
            name2.append(portion[0])
    Name1 = set(name1)
    Name2 = set(name2)
    diffs = Name1.difference(Name2)
    # Name1对比Name2，Name1中多出来的文件；注意，如果Name2里有Name1中没有的文件，也不会筛选出来
    print(diffs)

    c_list = list(diffs)
    a = open(
        r"C:\\Users\\libaolin\\Desktop\\OTHER\\health_code\\healthy_code_of_classmate\\contrust_result\\name_of_no_code.txt",
        "w", encoding='UTF-8')
    a.write(",".join(c_list))
    a.close()


if __name__ == '__main__':
    # 参照路径
    path1 = 'C:\\Users\\libaolin\\Desktop\\OTHER\\health_code\\healthy_code_of_classmate\\healthy_code_2021_09_05'
    # 对比路径
    path2 = 'C:\\Users\\libaolin\\Desktop\\OTHER\health_code\\healthy_code_of_classmate\\healthy_code_2021_09_07'
    diff_file(path1, path2)

注意事项：文件命名后缀可不一样，但是参考文件和对比文件的命名内容必须一致；否则会无法识别，后期博主会尝试改进！