[hdu2087]kmp水题

题意：求模板串在文本串中出现的次数（位置无交叉）。只需在找到的时候把模板串指针归0即可。

  1 #pragma comment(linker, "/STACK:10240000,10240000")

  2 

  3 #include <iostream>

  4 #include <cstdio>

  5 #include <algorithm>

  6 #include <cstdlib>

  7 #include <cstring>

  8 #include <map>

  9 #include <queue>

 10 #include <deque>

 11 #include <cmath>

 12 #include <vector>

 13 #include <ctime>

 14 #include <cctype>

 15 #include <set>

 16 #include <bitset>

 17 #include <functional>

 18 #include <numeric>

 19 #include <stdexcept>

 20 #include <utility>

 21 

 22 using namespace std;

 23 

 24 #define mem0(a) memset(a, 0, sizeof(a))

 25 #define mem_1(a) memset(a, -1, sizeof(a))

 26 #define lson l, m, rt << 1

 27 #define rson m + 1, r, rt << 1 | 1

 28 #define define_m int m = (l + r) >> 1

 29 #define rep_up0(a, b) for (int a = 0; a < (b); a++)

 30 #define rep_up1(a, b) for (int a = 1; a <= (b); a++)

 31 #define rep_down0(a, b) for (int a = b - 1; a >= 0; a--)

 32 #define rep_down1(a, b) for (int a = b; a > 0; a--)

 33 #define all(a) (a).begin(), (a).end()

 34 #define lowbit(x) ((x) & (-(x)))

 35 #define constructInt4(name, a, b, c, d) name(int a = 0, int b = 0, int c = 0, int d = 0): a(a), b(b), c(c), d(d) {}

 36 #define constructInt3(name, a, b, c) name(int a = 0, int b = 0, int c = 0): a(a), b(b), c(c) {}

 37 #define constructInt2(name, a, b) name(int a = 0, int b = 0): a(a), b(b) {}

 38 #define pchr(a) putchar(a)

 39 #define pstr(a) printf("%s", a)

 40 #define sstr(a) scanf("%s", a)

 41 #define sint(a) scanf("%d", &a)

 42 #define sint2(a, b) scanf("%d%d", &a, &b)

 43 #define sint3(a, b, c) scanf("%d%d%d", &a, &b, &c)

 44 #define pint(a) printf("%d\n", a)

 45 #define test_print1(a) cout << "var1 = " << a << endl

 46 #define test_print2(a, b) cout << "var1 = " << a << ", var2 = " << b << endl

 47 #define test_print3(a, b, c) cout << "var1 = " << a << ", var2 = " << b << ", var3 = " << c << endl

 48 

 49 typedef double db;

 50 typedef long long LL;

 51 typedef pair<int, int> pii;

 52 typedef multiset<int> msi;

 53 typedef set<int> si;

 54 typedef vector<int> vi;

 55 typedef map<int, int> mii;

 56 

 57 const int dx[8] = {0, 0, -1, 1, 1, 1, -1, -1};

 58 const int dy[8] = {-1, 1, 0, 0, 1, -1, 1, -1 };

 59 const int maxn = 2e5 + 7;

 60 const int md = 10007;

 61 const int inf = 1e9 + 7;

 62 const LL inf_L = 1e18 + 7;

 63 const double pi = acos(-1.0);

 64 const double eps = 1e-6;

 65 

 66 template<class T>T gcd(T a, T b){return b==0?a:gcd(b,a%b);}

 67 template<class T>bool max_update(T &a,const T &b){if(b>a){a = b; return true;}return false;}

 68 template<class T>bool min_update(T &a,const T &b){if(b<a){a = b; return true;}return false;}

 69 template<class T>T condition(bool f, T a, T b){return f?a:b;}

 70 template<class T>void copy_arr(T a[], T b[], int n){rep_up0(i,n)a[i]=b[i];}

 71 int make_id(int x, int y, int n) { return x * n + y; }

 72 

 73 struct KMP {

 74     int next[1000010];

 75     void GetNext(char s[]) {

 76         mem0(next);

 77         next[0] = next[1] = 0;

 78         for(int i = 1; s[i]; i++) {

 79             int j = next[i];

 80             while(j && s[i] != s[j]) j = next[j];

 81             next[i + 1] = s[j] == s[i]? j + 1 : 0;

 82         }

 83     }

 84     int find(char s[], char s2[]) {

 85         int j = 0, len = strlen(s2), ans = 0;

 86         for (int i = 0; s[i]; i++) {

 87             while (j && s[i] != s2[j]) j = next[j];

 88             if (s[i] == s2[j]) j++;

 89             if (j == len) {

 90                 ans++;

 91                 j = 0;

 92             }

 93         }

 94         return ans;

 95     }

 96 };

 97 

 98 KMP kmp;

 99 char s[maxn], s2[maxn];

100 

101 int main() {

102     //freopen("in.txt", "r", stdin);

103     while (scanf("%s", s)) {

104         if (s[0] == '#') break;

105         scanf("%s", s2);

106         kmp.GetNext(s2);

107         cout << kmp.find(s, s2) << endl;

108     }

109     return 0;

110 }

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