t= tuple()
t
()t=(1,2,3,‘a’,[1,2])
t
(1, 2, 3, ‘a’, [1, 2])t[4]
[1, 2]1 in t
True#查
2 not in t
False4 not in t
True#元组赋值
a=1
b=56
a,b=b,a
a
56b
1u=1,2,3,‘a’,[1,2,3]
t
(1, 2, 3, ‘a’, [1, 2])u
(1, 2, 3, ‘a’, [1, 2, 3])#,左右两边都是元组
n=1,
type(n)
m=(1)
type(m)
#注意括号不一定为元组
#必须有,
n=(1,)
type(n)
#等号两边元素长度相等
type(t[0])
def printa(*a):
print(a)
printa(1,2,3,‘dsa’,[1,2,3])
SyntaxError: invalid syntax
= RESTART: D:/Python/上课源码/11-10/a.py
(1, 2, 3, ‘dsa’, [1, 2, 3])
= RESTART: D:/Python/上课源码/11-10/a.py
(1, 2, 3, ‘dsa’, [1, 2, 3])
s=‘abc’
l=[1,2,30]
zip(s,l)
#解构
for i in zip(s,l):
print(i)
(‘a’, 1)
(‘b’, 2)
(‘c’, 30)
for m n in zip(s,l):
SyntaxError: invalid syntax
for m,n in zip(s,l):
print(m,n)
a 1
b 2
c 30