部门工资前三高的所有员工(sql练习)

Employee 表包含所有员工信息，每个员工有其对应的工号 Id，姓名 Name，工资 Salary 和部门编号 DepartmentId 。

+----+-------+--------+--------------+
| Id | Name  | Salary | DepartmentId |
+----+-------+--------+--------------+
| 1  | Joe   | 85000  | 1            |
| 2  | Henry | 80000  | 2            |
| 3  | Sam   | 60000  | 2            |
| 4  | Max   | 90000  | 1            |
| 5  | Janet | 69000  | 1            |
| 6  | Randy | 85000  | 1            |
| 7  | Will  | 70000  | 1            |
+----+-------+--------+--------------+

Department 表包含公司所有部门的信息。

+----+----------+
| Id | Name     |
+----+----------+
| 1  | IT       |
| 2  | Sales    |
+----+----------+

编写一个 SQL 查询，找出每个部门获得前三高工资的所有员工。例如，根据上述给定的表，查询结果应返回：

+------------+----------+--------+
| Department | Employee | Salary |
+------------+----------+--------+
| IT         | Max      | 90000  |
| IT         | Randy    | 85000  |
| IT         | Joe      | 85000  |
| IT         | Will     | 70000  |
| Sales      | Henry    | 80000  |
| Sales      | Sam      | 60000  |
+------------+----------+--------+

来源：力扣（LeetCode）
链接：https://leetcode-cn.com/problems/department-top-three-salaries
 

我的解答：

select d.Name as Department, e.Name as Employee, e.Salary as Salary 
from Employee as e 
inner join Department as d 
on d.Id = e.DepartmentId 
where 
(select 1 from 
(
select * from Employee 
where DepartmentId = e.DepartmentId 
group by Salary 
order by DepartmentId, Salary desc limit 3
) as h 
where h.Salary = e.Salary
) 
order by e.DepartmentId,e.Salary desc