1.条件编译指令,可以避免重复包含的错误
#ifndef_ACCOUNT_H_
#define_ACCOUNT_H_
.........
#endif_ACCOUNT_H_
2.合并时出了些问题,比如date和account的顺序导致dle找不到date
应将date放在前...算了!放弃你的想法
乖乖分成几个文件来写,要不然迟早玩完(微笑)
part1 account.h
//account.h
#ifndef __ACCOUNT_H__
#define __ACCOUNT_H__
#include "date.h"
#include
class SavingsAccount { //储蓄账户类
private:
std::string id; //帐号
double balance; //余额
double rate; //存款的年利率
Date lastDate; //上次变更余额的时期
double accumulation; //余额按日累加之和
static double total; //所有账户的总金额
//记录一笔帐,date为日期,amount为金额,desc为说明
void record(const Date &date, double amount, const std::string &desc);
//报告错误信息
void error(const std::string &msg) const;
//获得到指定日期为止的存款金额按日累积值
double accumulate(const Date& date) const {
return accumulation + balance * date.distance(lastDate);
}
public:
//构造函数
SavingsAccount(const Date &date, const std::string &id, double rate);
const std::string &getId() const { return id; }
double getBalance() const { return balance; }
double getRate() const { return rate; }
static double getTotal() { return total; }
//存入现金
void deposit(const Date &date, double amount, const std::string &desc);
//取出现金
void withdraw(const Date &date, double amount, const std::string &desc);
//结算利息,每年1月1日调用一次该函数
void settle(const Date &date);
//显示账户信息
void show() const;
};
#endif //__ACCOUNT_H__
part2 date.h
//date.h
#ifndef __DATE_H__
#define __DATE_H__
class Date { //日期类
private:
int year; //年
int month; //月
int day; //日
int totalDays; //该日期是从公元元年1月1日开始的第几天
public:
Date(int year, int month, int day); //用年、月、日构造日期
int getYear() const { return year; }
int getMonth() const { return month; }
int getDay() const { return day; }
int getMaxDay() const; //获得当月有多少天
bool isLeapYear() const { //判断当年是否为闰年
return year % 4 == 0 && year % 100 != 0 || year % 400 == 0;
}
void show() const; //输出当前日期
//计算两个日期之间差多少天
int distance(const Date& date) const {
return totalDays - date.totalDays;
}
};
#endif //__DATE_H__
part3 account.cpp
//account.cpp
#include "account.h"
#include
#include
using namespace std;
double SavingsAccount::total = 0;
//SavingsAccount类相关成员函数的实现
SavingsAccount::SavingsAccount(const Date &date, const string &id, double rate)
: id(id), balance(0), rate(rate), lastDate(date), accumulation(0) {
date.show();
cout << "\t#" << id << " created" << endl;
}
void SavingsAccount::record(const Date &date, double amount, const string &desc) {
accumulation = accumulate(date);
lastDate = date;
amount = floor(amount * 100 + 0.5) / 100; //保留小数点后两位
balance += amount;
total += amount;
date.show();
cout << "\t#" << id << "\t" << amount << "\t" << balance << "\t" << desc << endl;
}
void SavingsAccount::error(const string &msg) const {
cout << "Error(#" << id << "): " << msg << endl;
}
void SavingsAccount::deposit(const Date &date, double amount, const string &desc) {
record(date, amount, desc);
}
void SavingsAccount::withdraw(const Date &date, double amount, const string &desc) {
if (amount > getBalance())
error("not enough money");
else
record(date, -amount, desc);
}
void SavingsAccount::settle(const Date &date) {
double interest = accumulate(date) * rate //计算年息
/ date.distance(Date(date.getYear() - 1, 1, 1));
if (interest != 0)
record(date, interest, "interest");
accumulation = 0;
}
void SavingsAccount::show() const {
cout << id << "\tBalance: " << balance;
}
part4 main
//6_25.cpp
#include "account.h"
#include
using namespace std;
int main() {
Date date(2008, 11, 1); //起始日期
//建立几个账户
SavingsAccount accounts[] = {
SavingsAccount(date, "S3755217", 0.015),
SavingsAccount(date, "02342342", 0.015)
};
const int n = sizeof(accounts) / sizeof(SavingsAccount); //账户总数
//11月份的几笔账目
accounts[0].deposit(Date(2008, 11, 5), 5000, "salary");
accounts[1].deposit(Date(2008, 11, 25), 10000, "sell stock 0323");
//12月份的几笔账目
accounts[0].deposit(Date(2008, 12, 5), 5500, "salary");
accounts[1].withdraw(Date(2008, 12, 20), 4000, "buy a laptop");
//结算所有账户并输出各个账户信息
cout << endl;
for (int i = 0; i < n; i++) {
accounts[i].settle(Date(2009, 1, 1));
accounts[i].show();
cout << endl;
}
cout << "Total: " << SavingsAccount::getTotal() << endl;
return 0;
}