LeetCode 345 反转字符串中的元音字母

今天是坚持写题解的第12天。 

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代码细节

可以写一个函数避免if语句过长的尴尬。

C语言代码实现

较易，省略解题思路。

int choose(char c);
char* reverseVowels(char* s) {
	int len = strlen(s);
	int left = 0, right = len - 1;
	while (left < right) {
		int cntl = 0, cntr = 0;
		if (choose(s[left])){
			cntl++;
		}
			if (choose(s[right])){
				cntr++;
			}
			if (cntl ==1&&cntr==1 ) {
				int temp = s[left];
				s[left] = s[right];
				s[right] = temp;
				left++;
				right--;
				continue;
			}
			if (cntl == 1) {
				right--;
				continue;
			}
			else if (cntr == 1) {
				left++;
				continue;
			}
			left++;
			right--;
	}
	return s;
}
int choose(char c) {
	return c == 'a' || c == 'A' ||
		c == 'e' || c == 'E' ||
		c == 'i' || c == 'I' ||
		c == 'o' || c == 'O' ||
		c == 'u' || c == 'U';

}