python datetime 加一个月_Python 按月增加datetime月份的问题
今天要为大家收集分享的Python学习代码为：Python 按月增加datetime月份的问题源码。可能有同学看不明白什么是Python 按月增加datetime？其实简单的理解python datetime增加月份的问题，就是一些人的日常工作是需要对月份加减进行相关操作计算。
DateTime是什么：DateTime是时间类型，datetime是Python处理日期和时间的标准库。还有python time模块
Python 按月增加datetime月份的问题源码如下：（Python源码中注释部分多为英文，大家可自行翻译）
#coding=utf-8
import datetime
# input datetime1, and an month offset
# return the result datetime
def datetime_offset_by_month(datetime1, n = 1):
# create a shortcut object for one day
one_day = datetime.timedelta(days = 1)
# first use div and mod to determine year cycle
q,r = divmod(datetime1.month + n, 12)
# create a datetime2
# to be the last day of the target month
datetime2 = datetime.datetime(
datetime1.year + q, r + 1, 1) - one_day
'''
if input date is the last day of this month
then the output date should also be the last
day of the target month, although the day
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may be different.
for example:
datetime1 = 8.31
datetime2 = 9.30
'''
if datetime1.month != (datetime1 + one_day).month:
return datetime2
'''
if datetime1 day is bigger than last day of
target month, then, use datetime2
for example:
datetime1 = 10.31
datetime2 = 11.30
'''
if datetime1.day >= datetime2.day:
return datetime2
'''
then, here, we just replace datetime2's day
with the same of datetime1, that's ok.
'''
return datetime2.replace(day = datetime1.day)
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d1 = datetime.datetime(2008, 8, 17)
d2 = datetime_offset_by_month(d1, 13)
print '2008-8-17 + 13 month'
print d2
d1 = datetime.datetime(2008, 8, 31)
d2 = datetime_offset_by_month(d1, 13)
print '2008-8-31 + 13 month'
print d2
d1 = datetime.datetime(2007, 1, 30)
d2 = datetime_offset_by_month(d1, 13)
print '2007-1-30 + 13 month'
print d2
result = """
2008-8-17 + 13 month
2009-09-17 00:00:00
2008-8-31 + 13 month
2009-09-30 00:00:00
2007-1-30 + 13 month
2008-02-29 00:00:00
"""
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