python贪吃蛇代码-用python实现贪吃蛇代码

import sys, pygame

from pygame.locals import *

from random import randrange

up =lambda x:(x[0]-1,x[1])

down = lambda x :(x[0]+1,x[1])

left = lambda x : (x[0],x[1]-1)

right = lambda x : (x[0],x[1]+1)

tl = lambda x :x<3 and x+1 or 0

tr = lambda x :x==0 and 3 or x-1

dire = [up,left,down,right]

move = lambda x,y:[y(x[0])]+x[:-1]

grow = lambda x,y:[y(x[0])]+x

s = [(5,5),(5,6),(5,7)]

d = up

food = randrange(0,30),randrange(0,40)

FPSCLOCK=pygame.time.Clock()

pygame.init()

pygame.display.set_mode((800,600))

pygame.mouse.set_visible(0)

screen = pygame.display.get_surface()

screen.fill((0,0,0))

times=0.0

while True:

time_passed = FPSCLOCK.tick(30)

if times>=150:

times =0.0

s = move(s,d)

else:

times +=time_passed

for event in pygame.event.get():

if event.type == QUIT:

sys.exit()

if event.type == KEYDOWN and event.key == K_UP:

s = move(s,d)

if event.type == KEYDOWN and event.key == K_LEFT:

d=dire[tl(dire.index(d))]

if event.type == KEYDOWN and event.key == K_RIGHT:

d=dire[tr(dire.index(d))]

if s[0]==food:

s = grow(s,d)

food =randrange(0,30),randrange(0,40)

if s[0] in s[1:] or s[0][0]<0 or s[0][0]

>= 30 or s[0][1]<0 or

s[0][1]>=40:

break

screen.fill((0,0,0))

for r,c in s:

pygame.draw.rect(screen,(255,0,0),(c*20,r*20,20,20))

pygame.draw.rect(screen,(0,255,0),(food[1]*20,food[0]*20,20,20))

pygame.display.update()