167. Two Sum II - Input array is sorted

问题描述:

Given an array of integers that is already sorted in ascending order, find two numbers such that they add up to a specific target number.
The function twoSum should return indices of the two numbers such that they add up to the target, where index1 must be less than index2. Please note that your returned answers (both index1 and index2) are not zero-based.
You may assume that each input would have exactly one solution and you may not use the same element twice.

example:

Input: numbers={2, 7, 11, 15}, target=9
Output: index1=1, index2=2


思路:两头向中间逼近,代码如下

    vector twoSum(vector& numbers, int target) {
        int l = 0;
        int r = numbers.size() -1;
        while(l < r){
            if(numbers[l] + numbers[r] == target){
                vector res{l+1,r+1};
                return res;
            }
            else if(numbers[l] + numbers[r] > target){
                r--;
            }
            else{
                l++;
            }
        }
    }

你可能感兴趣的:(167. Two Sum II - Input array is sorted)