python填充颜色 相邻不能同色_python – matplotlib：两行之间的连续色彩映射填充...
我找到了解决这个问题的方法.它建立在@Hooked的杰出而又hacky
solution之上.您可以从许多小方块创建2D网格.它不是最快的解决方案,但它应该非常灵活(比应用imshow到补丁的解决方案更多).
import numpy as np
import pylab as plt
#Plot a rectangle
def rect(ax, x, y, w, h, c,**kwargs):
#Varying only in x
if len(c.shape) is 1:
rect = plt.Rectangle((x, y), w, h, color=c, ec=c,**kwargs)
ax.add_patch(rect)
#Varying in x and y
else:
#Split into a number of bins
N = c.shape[0]
hb = h/float(N); yl = y
for i in range(N):
yl += hb
rect = plt.Rectangle((x, yl), w, hb,
color=c[i,:], ec=c[i,:],**kwargs)
ax.add_patch(rect)
#Fill a contour between two lines
def rainbow_fill_between(ax, X, Y1, Y2, colors=None,
cmap=plt.get_cmap("Reds"),**kwargs):
plt.plot(X,Y1,lw=0) # Plot so the axes scale correctly
dx = X[1]-X[0]
N = X.size
#Pad a float or int to same size as x
if (type(Y2) is float or type(Y2) is int):
Y2 = np.array([Y2]*N)
#No colors -- specify linear
if colors is None:
colors = []
for n in range(N):
colors.append(cmap(n/float(N)))
#Varying only in x
elif len(colors.shape) is 1:
colors = cmap((colors-colors.min())
/(colors.max()-colors.min()))
#Varying only in x and y
else:
cnp = np.array(colors)
colors = np.empty([colors.shape[0],colors.shape[1],4])
for i in range(colors.shape[0]):
for j in range(colors.shape[1]):
colors[i,j,:] = cmap((cnp[i,j]-cnp[:,:].min())
/(cnp[:,:].max()-cnp[:,:].min()))
colors = np.array(colors)
#Create the patch objects
for (color,x,y1,y2) in zip(colors,X,Y1,Y2):
rect(ax,x,y2,dx,y1-y2,color,**kwargs)
# Some Test data
X = np.linspace(0,10,100)
Y1 = .25*X**2 - X
Y2 = X
g = np.exp(-.3*(X-5)**2)
#Plot fill and curves changing in x only
fig, axs =plt.subplots(1,2)
colors = g
rainbow_fill_between(axs[0],X,Y1,Y2,colors=colors)
axs[0].plot(X,Y1,'k-',lw=4)
axs[0].plot(X,Y2,'k-',lw=4)
#Plot fill and curves changing in x and y
colors = np.outer(g,g)
rainbow_fill_between(axs[1],X,Y1,Y2,colors=colors)
axs[1].plot(X,Y1,'k-',lw=4)
axs[1].plot(X,Y2,'k-',lw=4)
plt.show()
结果是,