Python五子棋
文章目录
- 前言
- 一、五子棋
- 总结
前言
五月一了，今天，我们来做一个小游戏——五子棋。
一、五子棋
五子棋起源于中国，全国智力运动会竞技项目之一，是一种两人对弈的纯策略型棋类游戏。双方分别使用黑白两色的棋子，下在棋盘直线与横线的交叉点上，先形成五子连珠者获胜。
五子棋容易上手，老少皆宜，而且趣味横生，引人入胜。它不仅能增强思维能力，提高智力，而且富含哲理，有助于修身养性。
1.导入库：
import pygame
import sys
from pygame.locals import QUIT, KEYDOWN
import numpy as np2.初始化pygame：
pygame.init()
screen = pygame.display.set_mode((670, 670))
screen_color = [238, 154, 73] # 设置画布颜色,[238,154,73]对应为棕黄色
line_color = [0, 0, 0] # 设置线条颜色，[0,0,0]对应黑色
3.总代码：
import pygame
import sys
from pygame.locals import QUIT, KEYDOWN
import numpy as np
pygame.init()
screen = pygame.display.set_mode((670, 670))
screen_color = [238, 154, 73] # 设置画布颜色,[238,154,73]对应为棕黄色
line_color = [0, 0, 0] # 设置线条颜色，[0,0,0]对应黑色
def check_win(over_pos):
mp = np.zeros([15, 15], dtype=int)
for val in over_pos:
x = int((val[0][0]-27)/44)
y = int((val[0][1]-27)/44)
if val[1] == white_color:
mp[x][y] = 2
else:
mp[x][y] = 1
for i in range(15):
pos1 = []
pos2 = []
for j in range(15):
if mp[i][j] == 1:
pos1.append([i, j])
else:
pos1 = []
if mp[i][j] == 2:
pos2.append([i, j])
else:
pos2 = []
if len(pos1) >= 5:
return [1, pos1]
if len(pos2) >= 5:
return [2, pos2]
for j in range(15):
pos1 = []
pos2 = []
for i in range(15):
if mp[i][j] == 1:
pos1.append([i, j])
else:
pos1 = []
if mp[i][j] == 2:
pos2.append([i, j])
else:
pos2 = []
if len(pos1) >= 5:
return [1, pos1]
if len(pos2) >= 5:
return [2, pos2]
for i in range(15):
for j in range(15):
pos1 = []
pos2 = []
for k in range(15):
if i+k >= 15 or j+k >= 15:
break
if mp[i+k][j+k] == 1:
pos1.append([i+k, j+k])
else:
pos1 = []
if mp[i+k][j+k] == 2:
pos2.append([i+k, j+k])
else:
pos2 = []
if len(pos1) >= 5:
return [1, pos1]
if len(pos2) >= 5:
return [2, pos2]
for i in range(15):
for j in range(15):
pos1 = []
pos2 = []
for k in range(15):
if i+k >= 15 or j-k < 0:
break
if mp[i+k][j-k] == 1:
pos1.append([i+k, j-k])
else:
pos1 = []
if mp[i+k][j-k] == 2:
pos2.append([i+k, j-k])
else:
pos2 = []
if len(pos1) >= 5:
return [1, pos1]
if len(pos2) >= 5:
return [2, pos2]
return [0, []]
def find_pos(x, y):
for i in range(27, 670, 44):
for j in range(27, 670, 44):
L1 = i-22
L2 = i+22
R1 = j-22
R2 = j+22
if x >= L1 and x <= L2 and y >= R1 and y <= R2:
return i, j
return x, y
def check_over_pos(x, y, over_pos):
for val in over_pos:
if val[0][0] == x and val[0][1] == y:
return False
return True
flag = False
tim = 0
over_pos = []
white_color = [255, 255, 255]
black_color = [0, 0, 0]
while True:
for event in pygame.event.get():
if event.type in (QUIT, KEYDOWN):
sys.exit()
screen.fill(screen_color)
for i in range(27, 670, 44):
if i == 27 or i == 670-27:
pygame.draw.line(screen, line_color, [i, 27], [i, 670-27], 4)
else:
pygame.draw.line(screen, line_color, [i, 27], [i, 670-27], 2)
if i == 27 or i == 670-27:
pygame.draw.line(screen, line_color, [27, i], [670-27, i], 4)
else:
pygame.draw.line(screen, line_color, [27, i], [670-27, i], 2)
pygame.draw.circle(screen, line_color, [27+44*7, 27+44*7], 8, 0)
for val in over_pos:
pygame.draw.circle(screen, val[1], val[0], 20, 0)
res = check_win(over_pos)
if res[0] != 0:
for pos in res[1]:
pygame.draw.rect(screen, [238, 48, 167], [
pos[0]*44+27-22, pos[1]*44+27-22, 44, 44], 2, 1)
pygame.display.update()
continue
x, y = pygame.mouse.get_pos()
x, y = find_pos(x, y)
if check_over_pos(x, y, over_pos):
pygame.draw.rect(screen, [0, 229, 238], [x-22, y-22, 44, 44], 2, 1)
keys_pressed = pygame.mouse.get_pressed()
if keys_pressed[0] and tim == 0:
flag = True
if check_over_pos(x, y, over_pos):
if len(over_pos) % 2 == 0:
over_pos.append([[x, y], black_color])
else:
over_pos.append([[x, y], white_color])
if flag:
tim += 1
if tim % 50 == 0:
flag = False
tim = 0
pygame.display.update()
总结
五月一了，你快乐了吗？
有志者，事竟成，破釜沉舟，百二秦关终属楚;苦心人，天不负，卧薪尝胆，三千越甲可吞吴。