vue3 elementPlus表单里面如何一次性校验多个表单

业务中有时候会碰见多个表单一起提交的场景,每个表单都有校验，官方文档中没有看到这种解决方法

我们可以用promise.all来处理 多个表单校验

–
定义每个表单验证的规则和名称

//基本信息表单验证
const basicFormRef = ref<FormInstance>()
const basicRules = reactive<FormRules>({
  workArea: [{ required: true, message: '请选择社区', trigger: 'change' }],
  workStreet: [{ required: true, message: '请选择街道', trigger: 'change' }],
  reservationTime: [{ required: true, message: '请选择预约时间', trigger: 'change' }]
})
//老人信息表单验证
const oldmanFormRef = ref<FormInstance>()
const oldmanRules = reactive<FormRules>({
  servicePeople: [{ required: true, message: '请选择老人', trigger: 'blur' }]
})
//工单信息表单验证
const workTypeFormRef = ref<FormInstance>()
const workTypeRules = reactive<FormRules>({
  workType: [{ required: true, message: '请选择工单类型', trigger: 'change' }]
})
//派单信息表单验证
const sendFormRef = ref<FormInstance>()
const sendRules = reactive<FormRules>({
  isWork: [{ required: true, message: '请选择是否指派', trigger: 'change' }]
})

第二步

提交按钮 绑定事件

原理就是 在方法里面 定义多个函数来校验单个表单规则,最后通过Promise.all[]来并行 处理返回的结果

<el-button type="primary" @click="affirmSubmit">提交</el-button>

/**
 * 模块名:校验多个表单
 * 代码描述:
 * 作者:Fant
 * 创建时间:2023/06/10 11:48:40
 */
const affirmSubmit = async () => {
  //基本信息校验
  const refBasicForm = async (formEl) => {
    if (!formEl) return
    return await formEl._value.validate((valid: any) => {
      console.log(valid)
    })
  }
  //老人信息校验
  const refOldmanForm = async (formEl) => {
    if (!formEl) return
    return await formEl._value.validate((valid: any) => {
      console.log(valid)
    })
  }
  //工单信息校验
  const refWorkTypeForm = async (formEl) => {
    if (!formEl) return
    return await formEl._value.validate((valid: any) => {
      console.log(valid)
    })
  }
  //派单信息校验
  const refSendForm = async (formEl) => {
    if (!formEl) return
    return await formEl._value.validate((valid: any) => {
      console.log(valid)
    })
  }
  const formRes = await Promise.all([
    refBasicForm(basicFormRef),
    refOldmanForm(oldmanFormRef),
    refWorkTypeForm(workTypeFormRef),
    refSendForm(sendFormRef)
  ])
  console.log(formRes)
  //判断当前并行返回的校验
  if (formRes[0] == true && formRes[1] == true && formRes[2] == true && formRes[3] == true) {
    console.log('校验通过')
  } else {
    console.log('校验错误')
  }
}