LeetCode-----57. Insert Interval(数组插入并重新合并)

Given a set of non-overlapping intervals, insert a new interval into the intervals (merge if necessary).

You may assume that the intervals were initially sorted according to their start times.

Example 1:
Given intervals [1,3],[6,9], insert and merge [2,5] in as [1,5],[6,9].

Example 2:
Given [1,2],[3,5],[6,7],[8,10],[12,16], insert and merge [4,9] in as [1,2],[3,10],[12,16].

This is because the new interval [4,9] overlaps with [3,5],[6,7],[8,10].

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/**
 * Definition for an interval.
 * public class Interval {
 *     int start;
 *     int end;
 *     Interval() { start = 0; end = 0; }
 *     Interval(int s, int e) { start = s; end = e; }
 * }
 */
public class Solution {
    public List insert(List intervals, Interval newInterval) {
        if (newInterval == null || intervals == null) {
            return intervals;
        }

        List results = new ArrayList();
        int insertPos = 0;

        for (Interval interval : intervals) {
            if (interval.end < newInterval.start) {
                results.add(interval);
                insertPos++;
            } else if (interval.start > newInterval.end) {
                results.add(interval);
            } else {
                newInterval.start = Math.min(interval.start, newInterval.start);
                newInterval.end = Math.max(interval.end, newInterval.end);
            }
        }

        results.add(insertPos, newInterval);

        return results;
    }
}