解决js计算小数不准的问题

1.使用计算函数

function accAdd(arg1, arg2) {

    var r1, r2, m;

    try { r1 = arg1.toString().split(".")[1].length } catch (e) { r1 = 0 };

    try { r2 = arg2.toString().split(".")[1].length } catch (e) { r2 = 0 };

    m = Math.pow(10, Math.max(r1, r2));

    return (arg1 * m + arg2 * m) / m;

}





function accSub(arg1, arg2) {

    var r1,r2,m,n;

    try{r1=arg1.toString().split(".")[1].length}catch(e){r1=0}

    try{r2=arg2.toString().split(".")[1].length}catch(e){r2=0}

    m=Math.pow(10,Math.max(r1,r2));

    n=(r1>=r2)?r1:r2;

    return ((arg1*m-arg2*m)/m).toFixed(n);

}





function accMul(arg1, arg2) {

    var m = 0, s1 = arg1.toString(), s2 = arg2.toString();

    try { m += s1.split(".")[1].length } catch (e) { }

    try { m += s2.split(".")[1].length } catch (e) { }

    return Number(s1.replace(".", "")) * Number(s2.replace(".", "")) / Math.pow(10, m)

}





function accDiv(arg1, arg2) {

    var c, d, e = 0,

        f = 0;

    try {

        e = arg1.toString().split(".")[1].length;

    } catch (g) {}

    try {

        f = arg2.toString().split(".")[1].length;

    } catch (g) {}

    return c = Number(arg1.toString().replace(".", "")), d = Number(arg2.toString().replace(".", "")), accMul(c / d, Math.pow(10, f - e));

}

使用方法

  let arr = [4, 1.8, 5.8, 1.8, 5, 1.8]
  function accAdd(arg1, arg2) {
    var r1, r2, m;
    try { r1 = arg1.toString().split(".")[1].length } catch (e) { r1 = 0 }
    try { r2 = arg2.toString().split(".")[1].length } catch (e) { r2 = 0 }
    m = Math.pow(10, Math.max(r1, r2))
    return (arg1 * m + arg2 * m) / m
  } 
  let sum = 0;
  $.map(arr,function(v,i){
    sum = accAdd(sum,v)
  })
  console.log(sum);

2.使用math.js插件

常用的几个运算方法是:
解决js计算小数不准的问题_第1张图片

<script src="https://cdnjs.cloudflare.com/ajax/libs/mathjs/5.0.0/math.js"></script>
<script>
  let arr = [4, 6, 5.8, 1.8, 5, 1.888888]

  let sum = 0;
  $.map(arr,function(v,i){
    sum = math.number(math.add(math.bignumber(v),math.bignumber(sum)))
    console.log(sum);
  })
  console.log(typeof(sum));

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