利用xpath+re获取中医宝典中的中药详情信息

完整代码

from lxml import etree
import requests
import re

def spider(name,img_path):
    url="http://zhongyibaodian.com/zhongcaoyaotupian/"+name+".html"
    headers = {
            'User-Agent': 'Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/88.0.4324.96 Safari/537.36 Edg/88.0.705.56'
        }

    page_text=requests.get(url=url,headers=headers)
    #如果不加这个会解析出乱码
    page_text.encoding="gb23112"
    page_text=page_text.text

    ex=''
    a_list=re.findall(ex,page_text,re.S)
    # print(a_list)
    for a in a_list:
        page_text=page_text.replace(a,"")
    page_text=page_text.replace("
","")
    page_text=page_text.replace("","")
    # print(page_text)

    tree=etree.HTML(page_text)

    #获取中药名称
    title=tree.xpath('//*[@id="divMain"]/div/h1/text()')[0]
    # print(title)

    #获取中药的详情信息
    result=""
    content=tree.xpath('//div[@class="spider"]/p[4]/text()')
    if content!=[]:
        p_list = tree.xpath('//div[@class="spider"]/p/text()')
        for p in p_list:
            result += p

    else:
        content=tree.xpath('//div[@class="spider"]/p[3]/text()')
        if content==[]:
            content=tree.xpath('//div[@class="spider"]/p[2]/text()')
        result=content[0]
    result=result.replace("【","\n【")
    # print(result)
    with open(img_path,'a') as fp:
        fp.write("名称:"+title+'\n'+result+'\n\n\n')



#解表药
##辛温解表药
xinwenjiebiaoyao=['mahuang','guizhi','xixin','jingjie','fangfeng','baizhi','qianghuo','gaoben','xinyi','sugeng','chengliu',
                  'congbai','husui','shengjiang']

for name in xinwenjiebiaoyao:
    spider(name,'../中药信息/解表药/辛温解表药.txt')
    print(name+'爬取成功！')


##二、辛凉解表药
xinliangjiebiaoyao=['baohe','niubangzi','chantui','sangye','juhua','yejuhua','shengma','chaihu','gegen','manjingzi','fuping',
                    'muzei','gehua','dandouchi','dadouhuangjuan','heizha']

for name in xinliangjiebiaoyao:
    spider(name,'../中药信息/解表药/辛凉解表药.txt')
    print(name+'爬取成功！')

代码讲解

首先我们利用xpath找到这一段。

但是我们解析出来是这样的，看到看到a标签中的数据并没有解析出来。

因此我可利用正则表达式将符合条件的a标签去掉，只留下其中的文本内容。

ex=''
a_list=re.findall(ex,page_text,re.S)
for a in a_list:
    page_text=page_text.replace(a,"")
page_text=page_text.replace("
","")
page_text=page_text.replace("","")

此时我们在解析出来就是这样

获得的就是只有一个元素的列表

因为此网站的页面设计并不是统一的，因此我们需要判断多种情况，在爬取的时候才不会出现例外

content=tree.xpath('//div[@class="spider"]/p[4]/text()')
    if content!=[]:
        p_list = tree.xpath('//div[@class="spider"]/p/text()')
        for p in p_list:
            result += p

    else:
        content=tree.xpath('//div[@class="spider"]/p[3]/text()')
        if content==[]:
            content=tree.xpath('//div[@class="spider"]/p[2]/text()')
        result=content[0]

最后结果