笔试强训

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Day3

字符串中找出最长的字符串

mycode：

#include 
#include

using namespace std;

int main() {
    vector<string> v;
    string str;
    getline(cin,str);
    for(int i =0;i<str.size();i++)
    {
        string s;
        while(isdigit(str[i]))
        {
            s.push_back(str[i++]);
        }
        v.push_back(s);
    }
    string longdigit = v[0];
    for(int i = 1;i<v.size();i++)
    {
          if(v[i].size()>longdigit.size())
          {
            longdigit = v[i];
          }
    }
    cout<<longdigit<<endl;

}

数组中出现超过一半的数字

mycode:

class Solution {
public:
    /**
     * 代码中的类名、方法名、参数名已经指定，请勿修改，直接返回方法规定的值即可
     *
     *
     * @param numbers int整型vector
     * @return int整型
     */
    int MoreThanHalfNum_Solution(vector<int>& numbers) {
        //求出数组的一半长度
        int halfsize = 0;
        if (numbers.size() % 2)
            halfsize = (numbers.size() - 1) / 2;
        else
            halfsize = (numbers.size()) / 2;
        //对其排序
        sort(numbers.begin(), numbers.end());
        int maxnum;
        for (int i = 0; i < numbers.size(); i++)
        {
            int count = 1;
            while (i != numbers.size()-1 && numbers[i] == numbers[i + 1])
            {
                count++;
                i++;
            }
            if (count > halfsize)
            {
                maxnum = numbers[i - 1];
            }
        }
        return maxnum;
    }
};