#遍历:嵌套列表, 将其中同位置的元素组成新的列表
lsts = [[1,2,3], [4,5,6],[7,8,9],[10,11,12]]
方法一：
ret_x = [x for [x,y,z] in lsts]
ret_y = [y for [x,y,z] in lsts]
ret_z = [z for [x,y,z] in lsts]
print(ret_x) #[1, 4, 7, 10]
print(ret_y) #[2, 5, 8, 11]
print(ret_z) #[3, 6, 9, 12]
打印结果:
[1, 4, 7, 10]
[2, 5, 8, 11]
[3, 6, 9, 12]
方法二：
ret_x=[x[0] for x in lsts]
ret_y=[x[1] for x in lsts]
ret_z=[x[2] for x in lsts]
print(ret_x) #[1, 4, 7, 10]
print(ret_y) #[2, 5, 8, 11]
print(ret_z) #[3, 6, 9, 12]
打印结果同上:
[1, 4, 7, 10]
[2, 5, 8, 11]
[3, 6, 9, 12]