dp含义:dp[i][j] 以i-1为结尾的s中有以j-1为结尾的t的个数
递推公式:
if (s[i - 1] == t[j - 1]) dp[i][j] = dp[i - 1][j - 1] + 1;
else dp[i][j] = dp[i][j - 1];
初始化:第一行第一列初始化
遍历顺序:从上到下 从左到右
class Solution {
public:
bool isSubsequence(string s, string t) {
vector> dp(s.size() + 1, vector(t.size() + 1, 0));
for (int i = 1; i <= s.size(); i++) {
for (int j = 1; j <= t.size(); j++) {
if (s[i - 1] == t[j - 1]) dp[i][j] = dp[i - 1][j - 1] + 1;
else dp[i][j] = dp[i][j - 1];
}
}
if (dp[s.size()][t.size()] == s.size()) return true;
return false;
}
};
先了解