412. Fizz Buzz

412. Fizz Buzzhttps://leetcode-cn.com/problems/fizz-buzz/

 

难度简单156

给你一个整数 n ，找出从 1 到 n 各个整数的 Fizz Buzz 表示，并用字符串数组 answer（下标从 1 开始）返回结果，其中：

• answer[i] == "FizzBuzz" 如果 i 同时是 3 和 5 的倍数。
• answer[i] == "Fizz" 如果 i 是 3 的倍数。
• answer[i] == "Buzz" 如果 i 是 5 的倍数。
• answer[i] == i 如果上述条件全不满足。

示例 1：

输入：n = 3
输出：["1","2","Fizz"]

示例 2：

输入：n = 5
输出：["1","2","Fizz","4","Buzz"]

示例 3：

输入：n = 15
输出：["1","2","Fizz","4","Buzz","Fizz","7","8","Fizz","Buzz","11","Fizz","13","14","FizzBuzz"]

提示：

• 1 <= n <= 104

通过次数103,833提交次数146,513

class Solution {
    public List fizzBuzz(int n) {
        List ans = new ArrayList();
        for(int i=1;i<=n;i++)
        {
            if(i%3==0 && i%5==0) ans.add("FizzBuzz");
            else if(i%3==0) ans.add("Fizz");
            else if(i%5==0) ans.add("Buzz");
            else ans.add(Integer.toString(i));
        }
        return ans;
    }
}