Android Fragment中使用Arouter跳转到Activity后返回Fragment不回调onActivityResult

Fragment中通过路由跳转到Activity

  • 跳转传递参数

    通过Arouter跳转

  Postcard postcard = ARouter.getInstance().build(RouterConstant.ACTION_TRANSMANAGERACTIVITY1);
  Bundle bundle = new Bundle();
  bundle.putInt("code", 404);
  postcard.with(bundle); //设置bundle
  fragmentNavigation(postcard,10000);


  private void fragmentNavigation(Postcard postcard , int requestCode) { 
      LogisticsCenter.completion(postcard);
      Intent intent = new Intent(getActivity(),postcard.getDestination());
      intent.putExtras(postcard.getExtras());
      startActivityForResult(intent, requestCode);
  }
  • Activity中获取参数
    ARouter.getInstance().inject(this);
    num =  getIntent().getExtras().getInt("code");

注意传递的参数Bundle也可以如下传递Bundle参数
设置Bundle参数

postcard.withBundle("Bundle",bundle);

Activity中获取Bundle参数

getIntent().getBundleExtra("Bundle").getInt("code");

在Activity中返回时别忘记了设置结果或者参数:

setResult(Activity.RESULT_OK);

Fragment总就可以重写onActivityResult方法,在此方法获取上一个Activity返回来的数据了或者处理相关业务逻辑了;
注意onActivityResult方法中int requestCode, int resultCode的区别;

Android Fragment中使用Arouter跳转到Activity后返回Fragment不回调onActivityResult_第1张图片

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