随手编程题

一副从1到n的牌,每次从牌堆顶取一张放桌子上,再取一张放牌堆底,直到手机没牌,最后桌子上的牌是从1到n有序,设计程序,输入n,输出牌堆的顺序数组

 public static void init(int n) {
        LinkedList a = new LinkedList<>();
        LinkedList b = new LinkedList<>();
        for (int i = 0; i < n; i++) {
            b.add(i + 1);
        }
        reverse(a, b);
    }

    private static void reverse(LinkedList a, LinkedList b) {
        int c = b.pollLast();
        a.push(c);
        if (b.size() == 0) {
            System.out.println(a);
            return;
        }
        int d = a.pollLast();
        a.push(d);
        reverse(a, b);
    }

    public static void main(String[] args) {
        init(6);
    }

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