代码
'''
本函数通过三次样条插值法进行函数值计算
'''
import numpy as np
x = np.array([1,2,4,5])
y = np.array([1,3,4,2])
m = np.array([17/8,None,None,-19/8])
lens = len(x)
x_f = 3.0
h = np.zeros(lens-1)
a = np.zeros(lens)
b = np.zeros(lens)
n = np.zeros([lens,lens])
for i in range(len(h)):
h[i] = x[i+1] - x[i]
for i in range(1,len(a)-1):
a[i] = h[i-1]/(h[i]+h[i-1])
b[i] = 3*(((1-a[i])*(y[i]-y[i-1]))/h[i-1]+(a[i]*(y[i+1]-y[i]))/h[i])
a[0] = 1
b[0] = (3*(y[1]-y[0]))/h[0]
b[-1] = (3*(y[-1]-y[-2]))/h[-1]
for i in range(len(n)):
n[i][i] = 2
if i != len(n) - 1:
n[i][i + 1] = a[i]
if i != 0:
n[i][i-1] = 1 - a[i]
for i in range(len(n)-1):
if i == 0:
m[i+1] = (b[i] - n[i][i]*m[i])/a[i]
else:
m[i+1] = (b[i] - n[i][i]*m[i] - n[i][i-1]*m[i-1])/a[i]
p = 0
for i in range(len(x)-1):
if x[i] < x_f <= x[i + 1]:
p = i
break
if p == 0:
print('待求值点超出函数范围!')
exit()
fun_1 = (1+2*(x_f-x[p])/(x[p+1]-x[p]))*(((x_f-x[p+1])/(x[p]-x[p+1]))**2)*y[p]
fun_2 = (1+2*(x_f-x[p+1])/(x[p]-x[p+1]))*(((x_f-x[p])/(x[p+1]-x[p]))**2)*y[p+1]
fun_3 = (x_f-x[p])*(((x_f-x[p+1])/(x[p]-x[p+1]))**2)*m[p]
fun_4 = (x_f-x[p+1])*(((x_f-x[p])/(x[p+1]-x[p]))**2)*m[p+1]
fun = fun_1 + fun_2 + fun_3 + fun_4
print('函数在点 {0} 处的插值函数值为: {1} '.format(x_f,fun))