求n位自幂数

无意中看到介绍水仙花数，即一个3位数的各位数字的3次方和等该数本身

实际上就是自幂数的一种，感觉有点意思，写个脚本试了下

#!/usr/bin/python
# -*- coding: utf-8 -*-
import sys, time

def deco(func):
    def inner(*args, **kwargs):
        b_time = time.time()
        rlt = func(*args, **kwargs)
        e_time = time.time()
        print 'elapse:', e_time - b_time
        return rlt
    return inner

@deco
def daffodilNumber(bit):
    rlt = []
    start, end = pow(10, bit - 1), pow(10, bit)
    for i in range(start, end):
        if isDaffodilNumber(i):
            rlt.append(i)
    return rlt

def isDaffodilNumber(number):
    tmp, rlt = 0, False
    strNum = str(number)
    for i in strNum:
        tmp += pow(int(i), len(strNum))
    if tmp == number:
        rlt = True
    return rlt

if '__main__' == __name__:
    bit, lp = 0, []
    if len(sys.argv) > 1:
        bit = int(sys.argv[1])