c 语言计算十个人成绩平均数,(C语言)输入10个学生5门课的成绩, 分别用函数实现以下功能1.计算每个学生的平均分2.计算每门课的平均分3.找出50个分数最高的分数所对应的学生和课程4.计算平均方差...
输入10个学生5门课的成绩, 分别用函数实现以下功能1.计算每个学生的平均分2.计算每门课的平均分3.找出50个分数最高的分数所对应的学生和课程4.计算平均方差
#define _CRT_SECURE_NO_WARNINGS
#include
#include
#include
#define M 10
#define N 5
double stu_aver(int i, int a[M][N]) {//计算学生平均成绩
double sum = 0;
for (int j = 0; j < N; ++j) {
sum += a[i][j];
}
return sum / N;
}
void score_aver(int a[M][N]) {//科目平均成绩
double sum;
for (int i = 0; i < N; ++i) {
sum = 0;
printf("第%d门课的平均分为:\n", i + 1);
for (int j = 0; j < M; ++j) {
sum += a[j][i];
}
printf("%f\n", sum / M);
}
}
void top_score(int a[M][N]) {//最高分
int top = a[0][0];
int row = 0;
int col = 0;
int i, j;
for (i = 0; i < M; ++i) {
for (j = 0; j < N; ++j) {
if (a[i][j] > top) {
top = a[i][j];
row = i;
col = j;
}
}
}
printf("第%d个学生的第%d门成绩最高,为%d分\n",row + 1,col + 1, top);
}
double viriance(int a[M][N] ) {//方差
double x1 = 0;
double x2 = 0;
for (int i = 0; i < M; ++i)
{
x1 += stu_aver(i, a);
x2 += pow(stu_aver(i, a), 2);
}
return x2 / M - pow(x1 / M, 2);
}
void main() {
int stu_score[M][N] = { 0 };
for (int i = 0; i < M; ++i) {
printf("请输入第%d个学生的五门成绩\n", i + 1);
for (int j = 0; j < N; ++j) {
printf("第%d门成绩\n", j + 1);
scanf("%d", &stu_score[i][j]);
stu_score[i][j] = 1;
}
system("cls");
}
/*int stu_score[10][5] = { {70,80,90,40,50},
{60,70,80,30,50},
{90,80,90,93,94},
{100,80,96,95,94},
{50,60,70,90,67},
{71,83,90,40,50},
{67,70,88,30,50},
{90,86,90,93,94},
{100,80,93,95,94},
{50,60,50,90,67} };*///调试用
for (int i = 0; i < M; ++i) {
printf("student%d:\n", i + 1);
for (int j = 0; j < N; ++j) {
printf("%d\t", stu_score[i][j]);
}
printf("\n");
}
for (int i = 0; i < M; ++i) {
printf("第%d位学生的平均成绩为:\n%f\n", i + 1, stu_aver(i, stu_score));
}
score_aver(stu_score);
top_score(stu_score);
printf("方差为:%f\n", viriance(stu_score));
system("pause");
}
