2022-09-29 leetcode 1552 题目，不断优化

今天写leetcode 1552 题目，不断优化

class Solution:
    def maxDistance(self, position: List[int], m: int) -> int:
        def check(x: int) -> bool:
            pre = position[0]
            cnt = 1
            for i in range(1, len(position)):  #这里优化掉，不用range
                if position[i] - pre >= x:
                    pre = position[i]
                    cnt += 1
            return cnt >= m

        position.sort()
        left, right, ans = 1, position[-1] - position[0], -1
        while left <= right:
            mid = (left + right) // 2;
            if check(mid):
                ans = mid       #这里可以优化掉，赋值
                left = mid + 1
            else:
                right = mid - 1
        
        return ans   #返回left

作者：LeetCode-Solution
链接：https://leetcode.cn/problems/magnetic-force-between-two-balls/solution/liang-qiu-zhi-jian-de-ci-li-by-leetcode-solution/
来源：力扣（LeetCode）
著作权归作者所有。商业转载请联系作者获得授权，非商业转载请注明出处。

class Solution:
    def maxDistance(self, pp: List[int], m: int) -> int:
        pp.sort()
        k=len(pp)
        def check(x):
            cnt=1 
            p=pp[0]
            for i in range(1,k):
                if pp[i] -p >=x:
                    cnt+=1 
                    p=pp[i]
            return cnt>=m
        left=1
        right=pp[-1]
        while left>1
            if check(mid):
                left=mid
            else:
                right=mid-1
        return left

再一次优化

class Solution:
    def maxDistance(self, pp: List[int], m: int) -> int:
        pp.sort()
        k=len(pp)
        def check(x):
            cnt=1 
            p=pp[0]
            for i in pp:    #这里不切片，不range
                if i -p >= x:
                    cnt+=1 
                    p=i
            return cnt>=m
        left=1
        right=pp[-1]
        while left>1  #右手打法
            if check(mid):
                left=mid
            else:
                right=mid-1
        return left