PHP解析json 并获取元素的值

 $json=
 '{
 "item1":
 {"item11":{"n":"chenling","m":"llll"},"sex":"男","age":"25"},
 "item2":
 {"item21":"ling","sex":"女","age":"24"}
 }';
 $J=json_decode($json);
 echo "通过下面的信息就可以获取里面的信息了";
 print_r($J);
 print_r("");
 echo "测试访问对象内元素";
 print_r($J->item1->item11->n."");
 print_r($J->item1->sex."");
 //注意不是标准的json
 print_r($J->item2->age."");
 ?>