11. Container With Most Water

You are given an integer array height of length n. There are n vertical lines drawn such that the two endpoints of the ith line are (i, 0) and (i, height[i]).

Find two lines that together with the x-axis form a container, such that the container contains the most water.

Return the maximum amount of water a container can store.

Notice that you may not slant the container.

Example 1:

11. Container With Most Water_第1张图片

Input: height = [1,8,6,2,5,4,8,3,7]
Output: 49
Explanation: The above vertical lines are represented by array [1,8,6,2,5,4,8,3,7]. In this case, the max area of water (blue section) the container can contain is 49.

Example 2:

Input: height = [1,1]
Output: 1

class Solution {
    public int maxArea(int[] height) {
        if(height == null || height.length == 0){
            return 0;
        }
        int i=0, j=height.length-1; //两个指针往中间移动,每次选长的那个条
        int max = 0;
        while(i<=j){
            max = Math.max(max, Math.min(height[i],height[j]) * (j-i));
            if(height[i]<=height[j]){
                i++;
            }else{
                j--;
            }
        }
        return max;
    }
}

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