mysql把日期相减并按照区间范围统计

数据计算导入时间和审核时间之间的差并且按照时间区间，整理成excel画出图表。

关键的表字段如上图所示。

首先两个日期的加减涉及到mysql的函数datediff（），可以计算出两者之间的差值

SELECT
	fk_comp_id,
	datediff(
		LEFT (f_create_time, 8),
		LEFT (f_date, 8)
	)
FROM
	t_athlete_score
WHERE
	f_year = 2019
GROUP BY
	fk_comp_id

然后计算差值在什么范围之内，使用到mysql的函数INTERVAL()，INTERVAL()函数进行比较列表(N1，N2，N3等等)中的N值。该函数如果N

mysql>SELECT INTERVAL(6,1,2,3,4,5,6,7,8,9,10);
+---------------------------------------------------------+
| INTERVAL(6,1,2,3,4,5,6,7,8,9,10)                        |
+---------------------------------------------------------+
| 6                                                       |
+---------------------------------------------------------+
1 row in set (0.00 sec)

结果中，6是从零开始的索引，列表第一个值的值大于N. 在我们的例子中，6 属于 [6,7) ，所以返回第6个索引

sql可以演化为：

SELECT
	
		INTERVAL (
			datediff(
				LEFT (f_create_time, 8),
				LEFT (f_date, 8)
			),
			0,
			10,
			20,
			30,
			40,
			50,
			60,
			70,
			80,
			90,
			100,
			110,
			120
		) AS dayNumber,
	fk_comp_id,
	datediff(
		LEFT (f_create_time, 8),
		LEFT (f_date, 8)
	)
FROM
	t_athlete_score
WHERE
	f_year = 2019
GROUP BY
	fk_comp_id

查询出来的结果，如图所示：

然后为了能更好看，表达的更清晰一点，可以使用ELT()函数，将每个值赋予意义，ELT(n,str1,str2,str3,…) ：如果n=1，则返回str1,如果n=2，则返回str2,依次类推。如果n小于1或大于参数个数，返回NULL。

mysql> SELECT ELT(3,'hello','halo','test','world');
+--------------------------------------+
| ELT(3,'hello','halo','test','world') |
+--------------------------------------+
| test                                 |
+--------------------------------------+
1 row in set

此时，mysql的SQL语句演变为：

SELECT
	ELT(INTERVAL(datediff(LEFT (f_create_time, 8),LEFT (f_date, 8)),0,10,20,30,40,50,60,70,80,90,100,110,120),'<=10','10,'20,'30,'40,'50,'60,'70,'80,'90,'100,'110,'x>=120') as dayNumber,
	fk_comp_id,
datediff(LEFT (f_create_time, 8),LEFT (f_date, 8))
FROM
	t_athlete_score
WHERE
	f_year = 2019
GROUP BY
	fk_comp_id

然后统计每个区间的个数，sql演化为：

select m.dayNumber,count(fk_comp_id) from (
SELECT
	ELT(
		INTERVAL (
			datediff(
				LEFT (f_create_time, 8),
				LEFT (f_date, 8)
			),
			0,
			10,
			20,
			30,
			40,
			50,
			60,
			70,
			80,
			90,
			100,
			110,
			120
		),
		'<=10',
		'10,
		'20,
		'30,
		'40,
		'50,
		'60,
		'70,
		'80,
		'90,
		'100,
		'110,
		'x>=120'
	) AS dayNumber,
	fk_comp_id,
	datediff(
		LEFT (f_create_time, 8),
		LEFT (f_date, 8)
	),INTERVAL (
			datediff(
				LEFT (f_create_time, 8),
				LEFT (f_date, 8)
			),
			0,
			10,
			20,
			30,
			40,
			50,
			60,
			70,
			80,
			90,
			100,
			110,
			120
		) as orderindex
FROM
	t_athlete_score
WHERE
	f_year = 2019
GROUP BY
	fk_comp_id
) as m GROUP BY m.dayNumber ORDER BY m.orderindex

查询出来的结果为：

将查询结果，做成excel图表如下图：